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3 years ago

14/7x8-35/7x2 help me simplify using order of operations

1 answer:

3 0

4116 first answer 7 times 8 subtract 35.Second multiply by 14.Lastly solve 7 times 2 and multiply it by what you got multiplying 14.

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You don’t need to tell me the answer, but could you tell me the formula on how to get the answer ?

steposvetlana [31]

Formula used: cos(x) = $\frac{adjacent}{hypotenuse}$

Hope this helped!

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3 0

3 years ago

15. Construct the slope-intercept form equation of the line passing through (-5,23) and (10,-5).

Radda [10]

Answer:

15y = -28 x + 205.

Step-by-step explanation:

Slope intercept form of equation is y = mx + c where m is slope and c is the y intercept.

Now slope of line passing through points (-5, 23) and (10, -5):

$m = \frac{y_{2} - y_{1} }{x_{2} - x_{1} } = \frac{-5 -23}{10 + 5} = \frac{-28}{15}$

Now equation of line:

y = mx + c

substituting the value of m in above expression,

$y = -\frac{28}{15} x + c$

Now, since the line is passing through the point (-5, 23) therefore, x = -5 and y = 23. By substituting these values in above equation,

$23 = -\frac{28}{15} \times (-5) + c$

$23 = \frac{28}{3} + c$

$c = 23 - \frac{28}{3} = \frac{69 - 28}{3} = \frac{41}{3}$

So equation of line in slope intercept form:

$y = -\frac{28}{15} x + \frac{41}{3}$

Further solving,

15y = -28 x + 205.

3 0

3 years ago

What is the product? StartFraction 3 k Over k + 1 EndFraction times StartFraction k squared minus 1 Over 3 k cubed EndFraction S

Nana76 [90]

Answer:

StartFraction negative 1 Over k cubed EndFraction

Step-by-step explanation:

3k / (k + 1) × (k²- 1) / 3k³

= 3k(k² - 1) / (k + 1)(3k³)

= 3k³ - 3k / 3k⁴ + 3k³

= -3k / 3k⁴

= -1/k³

StartFraction k + 1 Over k squared EndFraction

(k + 1) / k²

StartFraction k minus 1 Over k squared EndFraction

(k - 1)/k²

StartFraction negative 1 Over k cubed EndFraction

= -1/k³

StartFraction 1 Over k EndFraction

= 1/k

4 0

3 years ago

Geometry homework!!!HELP ME PLEASE!!

Lady_Fox [76]

f= (45*23)/35

k=(35*14)/23

5 0

3 years ago

Write (5,0) with a slope of 2 in slope-intercept form

tia_tia [17]

Y = mx + c
y = 2x + c
When x = 5 and y = 0,
0 = 2(5) + c
c = -10

y = 2x - 10

6 0

3 years ago