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jasenka [17]
3 years ago
11

PLEASE HELP I WILL GIVE BRAINLIEST Complete the frequency table: Method of Travel to School Walk/Bike Bus Car Row totals Under a

ge 15 60 165 Age 15 and above 65 195 Column totals 152 110 98 360 What percentage of students under age 15 travel to school by car? Round to the nearest whole percent. 11% 18% 41% 80%

Mathematics
2 answers:
Ilya [14]3 years ago
6 0

Answer:

A. 11%

Step-by-step explanation:

frozen [14]3 years ago
3 0

Answer:

11%

Step-by-step explanation:

1. Fill out the table with the correct numbers.

2. After you fillout the numbers, you should notice that under the column car and in the first row, there should be the number 18.

3. We know the total number of students under the age of 15 is 165.

4. To find the percent:

       18/165 * 100

               = 11%

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Maura runs 5 miles in 1.25 hours. Ava runs 3 miles in 50 minutes or 0.83¯ hour.<br> Who runs faster?
kenny6666 [7]

Answer:

║⊕║∵°·∵∴Hello :)∴∵·°∵∴║⊕║

Your answer should be:

Maura runs faster.

Step-by-step explanation:

I hope this helped!

<em>Brainliest appreciated</em>

<h2><em>Have a good day!</em></h2>
8 0
3 years ago
There are 30 students in the school chorale, and 12 of these students can stay after school today to help prepare the stage for
gtnhenbr [62]
Well it would be 12/30 but it could divide by 2 which equals 6/15 which can be divided by 3 which equals 2/5 so the answer 2/5
8 0
3 years ago
ACTIVITY 2 (19) Mr Duma recently inherited a rectangular plot, part of the estate left by his late father. The plot with the fol
seraphim [82]

The sum of the lengths of three sides of the rectangle, gives the length

of the fencing, while one third of the rectangle area is for the pavement.

Responses:

Project A: The formula for the length of the fencing is, L = 4·x - 1

Project B: Length of the fancy wall = 2·x + 1

Project \ C:Area \ of \ the \ paving = \underline{ \dfrac{2\cdot x^2 }{3} - \dfrac{x }{3}  - \dfrac{1}{3}}

<h3>Which method can be used to find the length and area of paving from the given equations?</h3>

Project A: Let QP and SR represent the longest sides of the rectangle, we have;

PQ = SR = 2·x + 1

Given parameters are;

Length of the rectangular plot = 2·x + 1

Width of the rectangular plot = x - 1

Vertices of the rectangular plot are; QPSR

Project A: Let QP and SR represent the longest sides of the rectangle, we have;

PQ = SR = 2·x + 1

Which gives;

SP = QR = x - 1

The length of the fencing, L = SP + PQ + QR = x - 1 + 2·x + 1 + x - 1 = 4·x - 1

  • The formula for the length of the fencing is, L =<u> 4·x - 1</u>

Project B: The front side is SR

Therefore;

  • Length of the fancy wall = <u>2·x + 1</u>

Project C:

Area, A = Length × Width

Area of the plot, A = (2·x + 1) × (x - 1) = 2·x² - x - 1

  • Area \ of \ the \ paving = \dfrac{1}{3} \times \left(2 \cdot x^2 - x - 1\right) = \underline{ \dfrac{2\cdot x^2 }{3} - \dfrac{x }{3}  - \dfrac{1}{3}}

Learn more about writing equations here:

brainly.com/question/24760633

6 0
2 years ago
If 5x - 3y = 1 and x = 2y - 4, then x • y = ?
Inessa05 [86]

Answer:

x = 2,  y = 3

Step-by-step explanation:

i) It is given that 5x - 3y =1

ii) It is also given that x = 2y - 4

iii) we can substitute the value of x from ii) in the equation in i) and we will get 5(2y - 4) - 3y = 1   ⇒ 10y - 20 -3y =  1   ⇒  7y = 21  ∴ y = 3

iv) substituting the value of y obtained in ii) we get x = (2 × 3) - 4 = 6 - 4 = 2.

v) Therefore x = 2.

4 0
3 years ago
Can some one help me with these questions thank you
lisov135 [29]
Positive and a positive, will always be a positive because theyre both the same. If two things are the same, theyre equal. ( this is from what ik,I read it as a common sense question)
3 0
3 years ago
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