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3 years ago

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PLEASE HELP I WILL GIVE BRAINLIEST Complete the frequency table: Method of Travel to School Walk/Bike Bus Car Row totals Under a

ge 15 60 165 Age 15 and above 65 195 Column totals 152 110 98 360 What percentage of students under age 15 travel to school by car? Round to the nearest whole percent. 11% 18% 41% 80%

2 answers:

Ilya [14]3 years ago

6 0

Answer:

A. 11%

Step-by-step explanation:

frozen [14]3 years ago

3 0

Answer:

11%

Step-by-step explanation:

1. Fill out the table with the correct numbers.

2. After you fillout the numbers, you should notice that under the column car and in the first row, there should be the number 18.

3. We know the total number of students under the age of 15 is 165.

4. To find the percent:

18/165 * 100

= 11%

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Using the numbers -4, 10, 8, 2, -3, -5, write down two expressions that equal 6. You can use any relevant operation. You have to

Valentin [98]

Answer:

$\sf \Bigg[ \frac{ ( - 4 \times ( - 3)) }{2} \Bigg] \: and \: \Bigg[ \frac{ - ( - 5 \times 8)}{10} + 2 \Bigg]$

Step-by-step explanation:

Given:

$The \: numbers \rightarrow -4, 10, 8, 2, -3, -5$

To find:

Two expressions that equal 6 using the given numbers

Solution:

Expression first,

Using numbers -4, 2, -3,

aligning the above numbers as,

$\frac{ ( - 4 \times ( - 3)) }{2}$

will out put 6.

<em>Verification,</em>

$\frac{ ( - 4 \times ( - 3)) }{2} = \frac{12}{2} = \cancel\frac{12}{2} = 6$

Expression second,

Using numbers 10,8,2,-5

aligning the above numbers as,

$\frac{ - ( - 5 \times 8)}{10} + 2$

will result 6.

<em>Verification</em>

$\frac{ - ( - 5 \times 8)}{10} + 2 = \frac{ 40}{10} + 2 \\ \\ \frac{ - ( - 5 \times 8)}{10} + 2= 4 + 2 \\ \\\frac{ - ( - 5 \times 8)}{10} + 2 = 6$

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5 0

1 year ago

Help please Can you clear fractions in an equation by multiplying each side by a common denominator other than the LCD? Give an

Katena32 [7]

Yes here is an example:_

x/4 + 5/6 = 2

The LCD of 4 and 6 is 12 but we can also multiply through by 24 to clear the fractions:-

x/4 * 24 + 5/6 * 24 = 2 + 24

6x + 20 = 40

This will give us the same result if we multiplied through by 12.

7 0

2 years ago

Sharon is conducting research on two species of birds at a bird sanctuary. The number of birds of species A is represented by th

e-lub [12.9K]

Answer: After 7 years the number of birds of species A and B are same. and the number of birds during that year will be 140.

Step-by-step explanation:

Given: Sharon is conducting research on two species of birds at a bird sanctuary.

The number of birds of species A is represented by the equation below,where S represents the number of birds, x years after beginning her research.

$S=2^x+12$

The number of birds of species B is represented by the equation below,where S represents the number of birds, x years after beginning her research.

$S=15x+35$

To plot the above function, first find points by which they are passing.

For species A, At x=0 , $S=1+12=13$

At x=2 , $S=2+12=14$

Similarly find more points and plot curve on graph.

For species A, At x=0 , $S=0+35=35$

At x=2 , $S=15+35=50$

Plot a line with the help of these two points.

Now, from the graph the intersection of curve (for A) and line (for B) is at (7,140) which tells that After 7 years the number of birds of species A and B are same. and the number of birds during that year will be 140.

8 0

2 years ago

Read 2 more answers

Find all of the equilibrium solutions. Enter your answer as a list of ordered pairs (R,W), where R is the number of rabbits and

zloy xaker [14]

Answer:

$(0,0)$ $(4000,0)$ and $(500,79)$

Step-by-step explanation:

Given

See attachment for complete question

Required

Determine the equilibrium solutions

We have:

$\frac{dR}{dt} = 0.09R(1 - 0.00025R) - 0.001RW$

$\frac{dW}{dt} = -0.02W + 0.00004RW$

To solve this, we first equate $\frac{dR}{dt}$ and $\frac{dW}{dt}$ to 0.

So, we have:

$0.09R(1 - 0.00025R) - 0.001RW = 0$

$-0.02W + 0.00004RW = 0$

Factor out R in $0.09R(1 - 0.00025R) - 0.001RW = 0$

$R(0.09(1 - 0.00025R) - 0.001W) = 0$

Split

$R = 0$ or $0.09(1 - 0.00025R) - 0.001W = 0$

$R = 0$ or $0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

Factor out W in $-0.02W + 0.00004RW = 0$

$W(-0.02 + 0.00004R) = 0$

Split

$W = 0$ or $-0.02 + 0.00004R = 0$

Solve for R

$-0.02 + 0.00004R = 0$

$0.00004R = 0.02$

Make R the subject

$R = \frac{0.02}{0.00004}$

$R = 500$

When $R = 500$ , we have:

$0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

$0.09 -2.25 * 10^{-5} * 500 - 0.001W = 0$

$0.09 -0.01125 - 0.001W = 0$

$0.07875 - 0.001W = 0$

Collect like terms

$- 0.001W = -0.07875$

Solve for W

$W = \frac{-0.07875}{ - 0.001}$

$W = 78.75$

$W \approx 79$

$(R,W) \to (500,79)$

When $W = 0$ , we have:

$0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

$0.09 - 2.25 * 10^{-5}R - 0.001*0 = 0$

$0.09 - 2.25 * 10^{-5}R = 0$

Collect like terms

$- 2.25 * 10^{-5}R = -0.09$

Solve for R

$R = \frac{-0.09}{- 2.25 * 10^{-5}}$

$R = 4000$

So, we have:

$(R,W) \to (4000,0)$

When $R =0$ , we have:

$-0.02W + 0.00004RW = 0$

$-0.02W + 0.00004W*0 = 0$

$-0.02W + 0 = 0$

$-0.02W = 0$

$W=0$

So, we have:

$(R,W) \to (0,0)$

Hence, the points of equilibrium are:

$(0,0)$ $(4000,0)$ and $(500,79)$

4 0

2 years ago

Write the equation of the line that contains the point (-2 , 5) and is perpendicular to the line y = 1/2x + 3

horrorfan [7]

Answer:

no iea sorry

Step-by-step explanation:

7 0

2 years ago