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Xelga [282]
3 years ago
15

Four more than the product of 23 and Gregs height. Use the variable g to represent Gregs height

Mathematics
1 answer:
skad [1K]3 years ago
8 0
Four more than (4+) the product of 23 and gregs height (23 times greg's height)
greg's height will be represented by g
4+23g

23g means 23 times g same as 23(g)
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Is 83° and 83° a supplementary angles
Ainat [17]
No, supplementary angles have to be 180 degrees
However, 83+83=166 which does not equal to 180
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3 years ago
a small business has an average income of 3000 per month with a standard deviation of 250. if the income in a given month is 330
Vika [28.1K]

Answer:

<u>The correct answer is z = 1.2</u>

Step-by-step explanation:

μ or average income = US$ 3,000

σ or standard deviation = US$ 250

Income in a given month = US$ 3,300

For calculating the z score, we use the following formula:

z = (x – μ) / σ

z = (3,300 – 3,000 / 250)

z = 300/250

z = 6/5 = 1.2

Interpreting z

A Z score tells us how many units of standard deviation (1.2 in this case)from the average a given score is, that is, we do not count in quantity of points, but in quantities of standard deviations. To use the Z score we require the distribution to be normal and to know the average and standard deviation of the scores.

8 0
3 years ago
A rectangle has a height of k^2+3k 2 +3k, squared, plus, 3 and a width of k^2+7k 2 +7k, squared, plus, 7. Express the area of th
vlada-n [284]

Answer: k^4+10k^3+21k^2

Step-by-step explanation:

Given

Height of rectangle is h=k^2+3k

Width is w=k^2+7k

The area of the rectangle is given by the multiplication of the height and width

\Rightarrow A=\left(k^2+3k\right)\left(k^2+7k\right)\\\\\Rightarrow A=k^2k^2+k^2\cdot \:7k+3kk^2+3k\cdot \:7k\\\\\Rightarrow A=k^4+10k^3+21k^2

Thus, the area of the rectangle is k^4+10k^3+21k^2.

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Answer:

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Step-by-step explanation:

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The variable z varies jointly with x and y and inversely with v and w. Using the constant of variation,k, from the last problem,
antiseptic1488 [7]

Answer:

Step-by-step explanation:

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3 years ago
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