The answer is 3, and then 3 again
An arithmetic sequence starts with one number and you add the common difference to the previous term to get the current term
So...
f(x)=mx+b
m=common difference
b=starting point
f(11)=125=11m+b
-
f(1)=5=1m+b
--------
120=10m
Divide both sides by 10
12=m
Your common difference is 12.
I believe the answer is 60%
Answer:
The money my sister have is $34
Step-by-step explanation:
Given as :
The two statements are as
If I give my sister 5 dollars, then we will have the same amount of money ...A
If instead she gives me 8 dollars, then I'll have twice as much money as she has. ......B
Let the money I have = $x
And The money my sister have = $y
Now, From statement A
x - 5 = y + 5
or, x - y = 5 + 5
or, x - y = 10 ........1
Again, From statement B
2 ×(y - 8) = (x + 8)
2 y - 16 = x + 8
2 y - x = 24 ........2
Now, solving Eq 1 and 2
Put the value of x from eq 1 into eq 2
2 y - (y + 10) = 24
Or, 2 y - y = 24 + 10
Or, y = 34
So, The money my sister have = y = $34
Put the value of y into eq 1
so, x - 34 = 10
I.e x = 10 + 34
∴ x = 44
So, The money I have = x = $44
Hence, The money my sister have is $34 Answer
Answer:
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Step-by-step explanation:
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