Answer:
11,4 is the answers for the question
Step-by-step explanation:
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Answer:
A cardioid
Step-by-step explanation:
A cardioid is a curve in the shape of a heart traced by a point on the circumference of a circle as it rolls around a fixed circle of the same radius.
The equation of vertical cardioid is
± 
Given the polar curve is
4 
This is an equation of vertical cardioid.
So, it represents a cardioid.
For this case, we have to:
By definition, we know:
The domain of
is given by all real numbers.
Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. In the same way, its domain will be given by the real numbers, independently of the sign of the term inside the root. Thus, it will always be defined.
So, we have:
with
:
is defined.
with
is also defined.
has a domain from 0 to ∞.
Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. For it to be defined, the term within the root must be positive.
Thus, we observe that:
is not defined, the term inside the root is negative when
.
While
if it is defined for
.
Answer:

Option b
<h2>
Answer</h2>
After the dilation
around the center of dilation (2, -2), our triangle will have coordinates:



<h2>Explanation</h2>
First, we are going to translate the center of dilation to the origin. Since the center of dilation is (2, -2) we need to move two units to the left (-2) and two units up (2) to get to the origin. Therefore, our first partial rule will be:
→
Next, we are going to perform our dilation, so we are going to multiply our resulting point by the dilation factor
. Therefore our second partial rule will be:
→
→
Now, the only thing left to create our actual rule is going back from the origin to the original center of dilation, so we need to move two units to the right (2) and two units down (-2)
→
→
Now that we have our rule, we just need to apply it to each point of our triangle to perform the required dilation:













Now we can finally draw our triangle: