Answer:
- 2 trees ($200 from either service)
- c=100+50t
- c=80+60t
Step-by-step explanation:
It can work well to solve problems like this by considering how many times the difference in per-tree costs it takes to make up the difference in one-time costs.
Here the difference of one-time costs is $20, and the difference in per-tree costs is $10, so it takes the pruning of 2 trees for the per-tree cost difference to equal the one-time cost difference (2×10 = 20).
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The cost equations are ...
cost = (one-time cost) + (per tree cost) × (number of trees)
c = 100 + 50t . . . . . company A
c = 80 + 60t . . . . . . company B
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If you use these equations to solve the problem, you want to find t such that the two costs are equal:
100 +50t = 80 +60t
(100 -80) = t(60 -50) . . . . . . . subtract 80+50t, factor out t
(100 -80)/(60 -50) = t . . . . . . . looks a lot like the verbal description above
The difference in fixed price divided by the difference in per-tree cost) is the number of trees required to make costs equal.
Answer:
![\displaystyle d = 4\sqrt{5}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20d%20%3D%204%5Csqrt%7B5%7D)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
<u>Algebra II</u>
- Distance Formula:
![\displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20d%20%3D%20%5Csqrt%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D)
Step-by-step explanation:
<u>Step 1: Define</u>
Point (-5, 6) → x₁ = -5, y₁ = 6
Point (3, 2) → x₂ = 3, y₂ = 2
<u>Step 2: Find distance </u><em><u>d</u></em>
Simply plug in the 2 coordinates into the distance formula to find distance <em>d</em>
- Substitute in points [Distance Formulas]:
![\displaystyle d = \sqrt{(3+5)^2+(2-6)^2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20d%20%3D%20%5Csqrt%7B%283%2B5%29%5E2%2B%282-6%29%5E2%7D)
- [Distance] [√Radical] (Parenthesis) Add/Subtract:
![\displaystyle d = \sqrt{(8)^2+(-4)^2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20d%20%3D%20%5Csqrt%7B%288%29%5E2%2B%28-4%29%5E2%7D)
- [Distance] [√Radical] Evaluate exponents:
![\displaystyle d = \sqrt{64+16}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20d%20%3D%20%5Csqrt%7B64%2B16%7D)
- [Distance] [√Radical] Add:
![\displaystyle d = \sqrt{80}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20d%20%3D%20%5Csqrt%7B80%7D)
- [Distance] [√Radical] Simplify:
![\displaystyle d = 4\sqrt{5}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20d%20%3D%204%5Csqrt%7B5%7D)
Answer:
First, lets look at the side that is already labeled: 5 ft. There are two 5 ft. sides, so the total perimeter so far is 10. I actually compared the 5 ft. side to the side labeled x, and it appears that x = 10. The reason for this is that if you compare both sides, the x side is the same amount as two 5 ft. sides. To calculate the total perimeter, we need to add up the sides: 10 + 10 + 5 + 5 = 30 ft.
hope this helps.
Your question is a little bit unclear but I'll try to help:
When quantity increases, we can calculate it's percent increase using equation.
PERCENT INCREASE= (new amount−original amount)/original amount}
<span>
You can also multiply it by 100% go tet percent value.
</span>When quantity decreases, you can calculate it's percent increase using equation.
PERCENT DECREASE=(original amount−new amount)/original amount
You can also multiply it by 100% go tet percent value.<span>
</span>
Step-by-step explanation:
3bx-3 = -3+12x
3bx=-3+3+12x
3bx=12x
3bx/3=12x/3
bx=4x
bx/x=4x/x
b=4