PLEASE HELP ME WITH THIS QUESTION I REALLY NEED HELP

Mathematics

1 answer:

sergij07 [2.7K]3 years ago

5 0

The mean of the numbers is 99
Add them all up then divide by 6

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A spinner is divided into 12 equal-sized sections. Each section is labeled with a number.

vfiekz [6]

Answer:

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Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

15 Points!

Xelga [282]

$f(x)=\dfrac{x-5}{x^2-1}\\\\\text{the horizontal asymptotes}\\\\x^2-1=0\to x^2=1\to x=\pm\sqrt1\to x=-1\ \wedge\ x=1\\\\\text{the vertical asymptotes}\\\\y=\lim\limits_{x\to\pm\infty}\dfrac{x-5}{x^2-1}=\lim\limits_{x\to\pm\infty}\dfrac{\frac{x}{x^2}+\frac{5}{x^2}}{\frac{x^2}{x^2}-\frac{1}{x^2}}=\dfrac{0+0}{1-0}=0$

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2 years ago

10÷2[500÷5{6 + (21+7-24)}} can any one ????

Assoli18 [71]

Answer:

5,000

Step-by-step explanation:

=10÷2[500÷5{6+4}

=10÷2[500÷5×10]

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8 0

3 years ago

PLZ HELP WILL MARK BRAINLIEST

Fantom [35]

Answer:

g(x) = (1/6)(x +7)^2 -8

Step-by-step explanation:

The transformation ...

g(x) = a·f(x -h) +k

represents vertical scaling by a factor of 'a', right shift by h units, and up shift by k units. You want the function g(x) for f(x) = x^2, a = 1/6, h = -7, and k = -8. Those transformations give you ...

g(x) = (1/6)(x +7)^2 -8