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CaHeK987 [17]
3 years ago
8

There are 20 nickels in a dollar

Mathematics
1 answer:
Natasha_Volkova [10]3 years ago
3 0

answer: n = 20

Step-by-step explanation:To write an equation, define variables. n will be the number of nickels. d will be the number of dollars. We want to know the number of nickels so the equation will be equal to n. Since there are 20 nickels in each dollar, 1 dollar will have 20 nickels. 2 dollars will have 40 nickels or 2*20. For d dollars, it will be 20d.n = 20d

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Natali [406]
<span>C. 7x/9y is the correct answer.
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3 years ago
2. JENNIFER IS TRYING TO SAVE MONEY. SHE WILL TAKE $150.00 TO
lisov135 [29]

Hope this helps.

If not, go to: https://www.mathportal.org/calculators/financial-calculators/simple-interest-calculator.php

6 0
3 years ago
Find the volume of a cube that has the following dimensions:length=2x^2 width=x^3 height=x^2-6x+5 A) 4x^7-3x^6+8x^5 B) 2x^12-12x
fomenos

Answer:

Option D. 2x⁷ - 12x⁶ + 10x⁵

Step-by-step explanation:

From the question given:

Length (L) = 2x²

Width (w) = x³

Height (h) = x² - 6x + 5

Volume (V) =?

Volume (V) = length (L) x width (w) x height (h)

V = L x w x h

V = 2x² × x³ × x² - 6x + 5

V = (2x²) (x³) (x² - 6x + 5)

V = (2x⁵) (x² - 6x + 5)

Clear bracket

V = 2x⁷ - 12x⁶ + 10x⁵

Therefore, the volume of the cube is 2x⁷ - 12x⁶ + 10x⁵

4 0
3 years ago
Find the 50th term of 15, 9, 3, -3,...
MA_775_DIABLO [31]

Answer:-32 I THINK IM NOT 100 PERCENT POSITIVE

Step-by-step explanation:

8 0
3 years ago
The variance can never bea.zerob.larger than the standard deviationc.negatived.smaller than the standard deviation
MrRa [10]

Answer:

c.negative

True, by definition since the variance take in count the differences around the mean squared, then we can't have a negative value for a sum of square values.

Step-by-step explanation:

We need to remember that the variance is a measure of dispersion for a dataset respect to a measure of central tendency called the mean. The mean is defined as:

\bar x = \frac{\sum_{i=1}^n X_i}{n}

And the population mean is given by:

\mu= \frac{\sum_{i=1}^n X_i}{N}

The population variance is defined by:

\sigma^2 = \frac{\sum_{i=1}^n (X_i -\mu)^2}{N}

And the sample variance is defined as:

s^2= \frac{\sum_{i=1}^n (X_i -\bar x)}{n-1}

Now if we analyze the options we have this:

a.zero

False, if all the values are the same then the mean would be the same to the values and the difference between each value and the mean would 0 and indeed the variance would be 0.

b.larger than the standard deviation

False, if the population standard deviation is \sigma=2 then the variance would be \sigma^2 = 4 and as we can see is higher than the standard deviation

c.negative

True, by definition since the variance take in count the differences around the mean squared, then we can't have a negative value for a sum of square values.

d.smaller than the standard deviation

False, if the population standard deviation is \sigma=0.1 then the variance would be \sigma^2 = 0.01 and as we can see is lower than the standard deviation

7 0
3 years ago
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