Question

Y=(x^2-6x+14) Labeling the vertex

Answer 1

I leaerned this neat trick
you don't need to convert to vertex form

where
y=ax^2+bx+c
the x value of the vertex is -b/2a
the y value is found by inserting the x value of the vertex into the equation


so

1x^2-6x+14
-b/2a=-(-6)/2(1)=6/2=3
plug that in
y=x^2-6x+14
y=3^2-6(3)+14
y=9-18+14
y=5

the vertex is (3,5)