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Naya [18.7K]
3 years ago
7

Y=(x^2-6x+14) Labeling the vertex

Mathematics
1 answer:
zavuch27 [327]3 years ago
6 0
I leaerned this neat trick
you don't need to convert to vertex form

where
y=ax^2+bx+c
the x value of the vertex is -b/2a
the y value is found by inserting the x value of the vertex into the equation


so

1x^2-6x+14
-b/2a=-(-6)/2(1)=6/2=3
plug that in
y=x^2-6x+14
y=3^2-6(3)+14
y=9-18+14
y=5

the vertex is (3,5)
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