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Naya [18.7K]
3 years ago
7

Y=(x^2-6x+14) Labeling the vertex

Mathematics
1 answer:
zavuch27 [327]3 years ago
6 0
I leaerned this neat trick
you don't need to convert to vertex form

where
y=ax^2+bx+c
the x value of the vertex is -b/2a
the y value is found by inserting the x value of the vertex into the equation


so

1x^2-6x+14
-b/2a=-(-6)/2(1)=6/2=3
plug that in
y=x^2-6x+14
y=3^2-6(3)+14
y=9-18+14
y=5

the vertex is (3,5)
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Step-by-step explanation:

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3 years ago
Geometry <br> Introduction to chord lengths in a circle
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Can you please help me evaluate this problems
Fofino [41]

Answer:

16.   137

17.    89

18.   168

19.   50

20.  8

21.   96

22.   39

23.   5

24.   -2

25.   7

Step-by-step explanation:

We have to follow BODMAS which is the acronym for Bracket, Of, Division, Multiplication and Subtraction.

We have to perform our calculations in this order. i.e., Solve the calculations in a bracket first then of and so on.

a = 12; b = 9; c = 4

16. a² + b - c²          = (12)² + 9 - 4²      = 144 + 9 - 16 = 153 - 16      = 137

17. b² + 2a - c²        = 81 + 2(12) - 16    = 81 + 24 - 16 = 105 - 16      = 89

18. 2c(a + b)           = 2 · 4 (12 + 9)      = 8(21)                                  = 168

19. 4a + 2b - c²      = 4(12) + 2(9) - 4²  = (48 + 18 - 16 = 66 - 16       =  50

20. [a² ÷ (4b)] + c  = [12² ÷ 4(9)] + 4 = [144 ÷ 36] + 4 = 4 + 4          = 8

21. c²(2b - a)          = 4²(2(9) - 12) = 4²(18 - 12) = 16(6)                     = 96

22. [bc² + a] ÷ c     = [9(4²) + 12] ÷ 4 = [9(16) + 12] ÷ 4 = 156 ÷ 4     = 39

23. [2c³ - ab] ÷ 4   = [2(4)³ - 12(9)] ÷ 4 = [2(64) - 108] ÷ 4

                              = [128 - 108] ÷ 4 = 20 ÷ 4                                   = 5

24. 2(a - b)² - 5c   = 2(12 - 9)² - 5(4) = 2(3)² - 20 = 18 - 20              = -2

25. [b² - 2c²] ÷ [a + c - b]

                              = [9² - 2(4)²] ÷ [12 + 4 - 9] = [81 - 32] ÷ [16 - 9]

                             = 49 ÷ 7                                                                 = 7

8 0
4 years ago
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