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lukranit [14]
2 years ago
6

What's the formula to find this?

Mathematics
2 answers:
Komok [63]2 years ago
7 0
25 cubic centimeters....
Hope this helps! all you had to do it multipley <span />
Sveta_85 [38]2 years ago
3 0
V=BH that is the equation!
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Simplify 2√2-√3<br> ---------------<br> √2+√3
serious [3.7K]

Step-by-step explanation:

=  \frac{2 \sqrt{2}   -  \sqrt{3} }{ \sqrt{2} +  \sqrt{3}  }

=  \frac{2 \sqrt{2} -  \sqrt{3}  }{ \sqrt{2} +  \sqrt{3}  }  \times  \frac{ \sqrt{2} -  \sqrt{3}  }{ \sqrt{2} -  \sqrt{3}  }

= \frac{ 2( \sqrt{2}  -  \sqrt{3} )( \sqrt{2}  -  \sqrt{3} )}{ { \sqrt{2} }^{2} -  { \sqrt{3} }^{2}  }

=  \frac{2(2 -  \sqrt{6}  -  \sqrt{6} - 3) }{2 - 3}

=  \frac{2( - 1 - 2 \sqrt{6} )}{ - 1}

=  \frac{ - 2(1 + 2 \sqrt{6} )}{ - 1}

= 2(1 + 2 \sqrt{6} )

= 2 + 4 \sqrt{6}

6 0
1 year ago
Y=2x+9 what the answer
tekilochka [14]

Answer:

x=Y/2−9/2

Step-by-step explanation:

please mark brainliest :)

8 0
3 years ago
Select the correct answer. Which expression is equivalent to 8x^2^3 sqrt 375x + 2^3 sqrt 3x^7, if x=0?
natima [27]

Answer:

(8x^3)^ \frac{2}{3} \sqrt{75x^3}  + 2^3 \sqrt{ 3x^7} =28x^3\sqrt{3x}

Step-by-step explanation:

The question is poorly formatted. The original question is:

(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7

We have:

(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7

Open bracket

(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =(8^ \frac{2}{3} *x^{3* \frac{2}{3}}) \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}

(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =(8^ \frac{2}{3} *x^2) \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}

Express 8 as 2^3

(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =(2^{3* \frac{2}{3}} *x^2) \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}

(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =(2^2 *x^2) \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}

(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =4x^2 \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}

Express 2^3 as 8

(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}=4x^2 \sqrt{75x^3} + 8\sqrt{ 3x^7}

Expand each exponent

(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}=4x^2 \sqrt{25x^2 *3x} + 8\sqrt{ 3x * x^6}

Split

(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}=4x^2 \sqrt{25x^2} *\sqrt{3x} + 8\sqrt{3x} * \sqrt{x^6}

(8x^3)^ \frac{2}{3} \sqrt{75x^3}  + 2^3 \sqrt{ 3x^7} =4x^2 *5x *\sqrt{3x} + 8\sqrt{3x} * x^3

(8x^3)^ \frac{2}{3} \sqrt{75x^3}  + 2^3 \sqrt{ 3x^7} =20x^3\sqrt{3x} + 8x^3\sqrt{3x}

Factorize

(8x^3)^ \frac{2}{3} \sqrt{75x^3}  + 2^3 \sqrt{ 3x^7} =28x^3\sqrt{3x}

4 0
2 years ago
Read 2 more answers
3(2a-2)=2(3a-3) solve
Leviafan [203]

Answer:

its true or 0

Step-by-step explanation:

8 0
2 years ago
PLEASE! PLEASE! help!
qaws [65]
1.) The answer is 825.75 (multiply the given tax rates to the gross pay)
    2,785 x 13% federal taxes = 362.05
    2,785 x 9% state tax         = 250.65
    2,785 x 7.65% FICA          = <u>213.05
</u>                                                 825.75
<u>
</u>2.) The answer is 288.60 (multiply the interest rate to the balance, no need to add a late payment fee since they paid on 6/1, not after)
    2,748.56 x 10.5% = 288.60

3.) The answer is 182.13  (multiply the APR to the original purchase price, no need to add the sales tax)
<u />    1,500 x 11.75% = 182.13

4.) The answer is 371.92 (deduct the reward to the interest)
    Interest : 2,975.34 x 13.5% = 401.67
    Reward : 2,975.34 x 1%      = <u>  29.75</u>  
                                                    371.92

5.) The answer is  1,339.13 (deduct the interest to the monthly payment)
    Monthly payment : 2,236.00
    Monthly interest :   <u>   896.87</u> [(231,450 x 4.65%) / 12 months]
<u />                                    1,339.13

Hope this helps! :)
4 0
2 years ago
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