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Setler79 [48]
3 years ago
9

A ball is dropped from a height of 10 meters. Each time it bounces, it reaches 50 percent of its previous height. The total vert

ical distance down the ball has traveled when it hits the ground the fifth time is meters.
Mathematics
2 answers:
Elza [17]3 years ago
7 0

Answer:

28.75 m

Step-by-step explanation:

a) First Fall  d=10 m ( first Hit)

b) Second fall

    height = 5 m

    height lost = 5 m (second hit)

Total = 10 m

c) Third Fall

Height = 2.50 m

height lost = 2.50 m (third hit)

Total distance = 5 m

d) forth Fall

Height = 1.25 m

Height lost = 1.25 m (forth hit)

Total distance = 2.50 m

e) fifth Fall

Height = 0.625 m

Height Lost = 0.625 m (fifth hit)

Total Distance = 10+5*2+2.50*2+1.25*2+0.625*2

=10+10+5+2.50+1.25

=20+7.50+1.25

=27.50+1.25

=28.75 m

Answer

8_murik_8 [283]3 years ago
6 0

Answer:

By the fifth bounce, it would reach 31.25 centimeters

Step-by-step explanation:

10/2=5

5/2=2.5

2.5/2=1.25

1.25/2=0.625

0.625/2=0.3125

0.3125 meters multiplied by 100(to get centimeters) = 31.25 centimeters

I hope this was helpful <3

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Step-by-step explanation:

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Answer:

We conclude that seniors skip more than 2% of their classes at 0.01 level of significance.

Step-by-step explanation:

We are given that a professor wishes to discover if seniors skip more classes than freshmen. Suppose he knows that freshmen skip 2% of their classes.

He randomly samples a group of seniors and out of 2521 classes, the group skipped 77.

<u><em /></u>

<u><em>Let p = percentage of seniors who skip their classes.</em></u>

So, Null Hypothesis, H_0 : p \leq 2%   {means that seniors skip less than or equal to 2% of their classes}

Alternate Hypothesis, H_A : p > 2%   {means that seniors skip more than 2% of their classes}

The test statistics that will be used here is <u>One-sample z proportion</u> <u>statistics</u>;

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So, <u><em>test statistics</em></u>  =  \frac{\frac{77}{2521} -0.02}{{\sqrt{\frac{\frac{77}{2521}(1-\frac{77}{2521})}{2521} } } } }

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The value of the test statistics is 3.08.

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Therefore, we conclude that seniors skip more than 2% of their classes.

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vitfil [10]

Answer:

None of the answer choices.

Step-by-step explanation:

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8 0
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