A ball is dropped from a height of 10 meters. Each time it bounces, it reaches 50 percent of its previous height. The total vert ical distance down the ball has traveled when it hits the ground the fifth time is meters.
2 answers:
Answer:
28.75 m
Step-by-step explanation:
a) First Fall d=10 m ( first Hit)
b) Second fall
height = 5 m
height lost = 5 m (second hit)
Total = 10 m
c) Third Fall
Height = 2.50 m
height lost = 2.50 m (third hit)
Total distance = 5 m
d) forth Fall
Height = 1.25 m
Height lost = 1.25 m (forth hit)
Total distance = 2.50 m
e) fifth Fall
Height = 0.625 m
Height Lost = 0.625 m (fifth hit)
Total Distance = 10+5*2+2.50*2+1.25*2+0.625*2
=10+10+5+2.50+1.25
=20+7.50+1.25
=27.50+1.25
=28.75 m
Answer
Answer:
By the fifth bounce, it would reach 31.25 centimeters
Step-by-step explanation:
10/2=5
5/2=2.5
2.5/2=1.25
1.25/2=0.625
0.625/2=0.3125
0.3125 meters multiplied by 100(to get centimeters) = 31.25 centimeters
I hope this was helpful <3
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