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Setler79 [48]
3 years ago
9

A ball is dropped from a height of 10 meters. Each time it bounces, it reaches 50 percent of its previous height. The total vert

ical distance down the ball has traveled when it hits the ground the fifth time is meters.
Mathematics
2 answers:
Elza [17]3 years ago
7 0

Answer:

28.75 m

Step-by-step explanation:

a) First Fall  d=10 m ( first Hit)

b) Second fall

    height = 5 m

    height lost = 5 m (second hit)

Total = 10 m

c) Third Fall

Height = 2.50 m

height lost = 2.50 m (third hit)

Total distance = 5 m

d) forth Fall

Height = 1.25 m

Height lost = 1.25 m (forth hit)

Total distance = 2.50 m

e) fifth Fall

Height = 0.625 m

Height Lost = 0.625 m (fifth hit)

Total Distance = 10+5*2+2.50*2+1.25*2+0.625*2

=10+10+5+2.50+1.25

=20+7.50+1.25

=27.50+1.25

=28.75 m

Answer

8_murik_8 [283]3 years ago
6 0

Answer:

By the fifth bounce, it would reach 31.25 centimeters

Step-by-step explanation:

10/2=5

5/2=2.5

2.5/2=1.25

1.25/2=0.625

0.625/2=0.3125

0.3125 meters multiplied by 100(to get centimeters) = 31.25 centimeters

I hope this was helpful <3

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