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o-na [289]
3 years ago
9

PLEASE HELP!!!!! HURRY

Mathematics
1 answer:
svp [43]3 years ago
7 0
Its c first find area of the whole thing with piece cut out.(240) then of the cut out piece (12) 240-12=228 C
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The graph of a piecewise defined function is given. evaluate f(-2), f(0), f(1)
vfiekz [6]

Answer:

D

Step-by-step explanation:

because when x = -2 on the graph the y is -2 (-2,-2)

when the x values is 0 the y value is 1 (0,1)

and when x is 1 the y value is 2. (1,2)

hope this helps. have a good day

5 0
3 years ago
Can you help me with this one ? 
saveliy_v [14]
<span>(2x + 1)(x + 3) = 2x^2 + 6x + x + 3 = 2x^2 + 7x + 3    A.</span>
6 0
3 years ago
Read 2 more answers
Write the equation of a line that is perpendicular to y = 5 y=5y, equals, 5 and that passes through the point ( − 7 , − 5 ) (−7,
Jlenok [28]
The line of the equation perpendicular to y=5 and cuts through (-5,-7) will be given by
m(x-x1)=y-y1
where m=slope.
from y=0x+5, the slope of the perpendicular line m=0,
thus the equation will be:
0(x--5)=y--7
0=y+7
y=-7
The equation is y=-7
3 0
3 years ago
Read 2 more answers
A regression by a sample of 10 observations gives: Score=49.5+1.96 Study Hours. The sample mean of study hour is 10.5 and sum of
amm1812

Answer:

0.1463

Step-by-step explanation:

Number of observations = 10

Sample mean = 10.5

Sum of standard deviation = 264.5

X = 14

We are to calculate The leverage statistic for study hour 14 using the data above

= 1/10 + (14-10.5)²/264.5

= 1/10 + 3.5²/264.5

= 0.1 +12.25/264.5

= 0.1+0.04631

= 0.1463 is the leverage statistic for the study

4 0
3 years ago
A theatre collected $100 from all the 100 attendees in the audience. The prices of the tickets were $10 for adults, $3 for frien
monitta
You can write a system of equations, I'm pretty sure. 
the first equation would be 
10a+3f+.5c=100
and 
a+f+c=100

For the first equation, its the price of each ticket that adds up to 100 tickets
For the second equation, its the amount of people that adds up to 100 people.

I'm pretty sure this is the route to go but I haven't solved it for myself (yet) I'll probably comment the answer if you need me to
4 0
2 years ago
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