If you change the the sign of a points y coordnate from positive to negative,how will the location of the point change

Mathematics

1 answer:

Nat2105 [25]3 years ago

3 0

Answer:

Because Point X Will Change After Point Y Changes

Step-by-step explanation:

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A student writes an incorrect step while checking if the sum of the measures of the two remote interior angles of triangle ABC b

iragen [17]

The student made the mistake in Step 2.

It should be m∠o + m∠p = 180 (Supplementary angles)

If this is corrected, then, since m∠m + m∠n + m∠o = 180 from Step 1,

we have,

m∠m + m∠n + m∠o = m∠o + m∠p which is Step 3.

Cancelling m∠o both sides, we get,

m∠m + m∠n = m∠p which is Step 4.

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3 years ago

A women buys 23 pounds of potatoes. She gives 10% of them to a neighbor and 15% of them to her mother. How many pounds dose she

vlabodo [156]

Answer:

= 17.25 pounds (Answer)

Step-by-step explanation:

Potatoes she bought = 23 pounds

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Potatoes left with her= 23 — 5.75

= 17.25 pounds (Answer)

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2 years ago

Read 2 more answers

Whats the intrgral of <img src="https://tex.z-dn.net/?f=%20%5Cint%20%20%5Cfrac%7Bx%5E2%2Bx-3%7D%7B%28x%5E3%2Bx%5E2-4x-4%29%5E2%7

rosijanka [135]

$\displaystyle\int\frac{x^2+x-3}{(x^3+x^2-4x-4)^2}\,\mathrm dx$

Notice that $x^3+x^2-4x-4=x^2(x+1)-4(x+1)=(x-2)(x+2)(x+1)$ . Decompose the integrand into partial fractions:

$\dfrac{x^2+x-3}{(x-2)^2(x+2)^2(x+1)^2}$
$=\dfrac1{3(x+1)}-\dfrac{11}{32(x+2)}-\dfrac1{3(x+1)^2}-\dfrac1{16(x+2)^2}+\dfrac1{96(x-2)}+\dfrac1{48(x-2)^2}$

Integrating term-by-term, you get

$\displaystyle\int\frac{x^2+x-3}{(x^3+x^2-4x-4)^2}\,\mathrm dx$
$=-\dfrac1{48(x-2)}+\dfrac1{3(x+1)}+\dfrac1{16(x+2)}+\dfrac1{96}\ln|x-2|+\dfrac13\ln|x+1|-\dfrac{11}{32}\ln|x+2|+C$