Question

Use the three steps to solve the problem.

Answer 1

Y=660x+600x
where y is distance apart and x is time

2000=660x+600x
2000=x(660+600)
2000=x(1260)
2000/1260=x
1.587h= 1 hour and 25 minutes
at 1:25PM the plane will be 2000 miles apart

Answer 2

Answer:

At 1:53 pm They will be 2,000 miles apart

Step-by-step explanation:

Given :The eastbound plane flies at 660 mph and the westbound plane flies at 600 mph

To Find : At what time will they be 2,000 miles apart?

Solution :

The eastbound plane flies at 660 mph

Suppose after time t they will be  2,000 miles apart

So, distance traveled at this time by eastbound = Distance = Speed * time

Distance = 660t

The westbound plane flies at 600 mph

Suppose after time t they will be  2,000 miles apart

So, distance traveled at this time by west bound = Distance = Speed * time

Distance = 600t

So, to calculate t time at which they will be 2000 miles apart

$2000=(660+600)t$

$2000=1260t$

$\frac{2000}{1260} =t$

$1.58=t$

Since 1 hr = 60 minutes

So, 0.58 hours = 0.58*60 = 34.8 minutes

Thus after 1 hour 34 minutes they will be 2000 miles apart

Since they start at 12 noon

So, after 1 hour 53 minutes time will be 1:53 pm

Hence At 1:53 pm They will be 2,000 miles apart