Answer:
Step-by-step explanation:
Allow me to rewrite your question and hope it will fit the original one:
<em>Jackson recorded the growth of a plant over 10 weeks. The equation </em><em>y=0.25x+4</em><em> represents the height y in inches over time x in weeks what does the y intercept represent In terms of the situation</em>
My answer:
As we know that y intercept is the value of y at the point where the line crosses the y axis (the value of x =0)
So in this situation, if x= 0, it means the height of the tree (y-intercept) initially be at 4 at week 0.
Hope it will find you well.
So first you distribute the negative to the 6x and 13 which will flip the sign of both of them to -6x and -13 so take away the parentheses and the equation is now 7x-6x-13. You combine the x’s and you get 1x-13 or x-13
Answer: Let's solve your equation step-by-step.
2h−3=3
Step 1: Add 3 to both sides.
2h−3+3=3+3
2h=6
Step 2: Divide both sides by 2.
2h/2 = 6/2
h = 3.
(-2)(-24)
(-3)(-16)
(-4)(-12)
(-6)(-8)
-(-1)(-48)
1*48
2*24
3*16
4*12
6*8
Answer:
a)= 2
b) 6.324
c) P= 0.1217
Step-by-step explanation:
a) The mean of the sampling distribution of X`1- X`2 denoted by ux`-x` = u1-u2 is equal to the difference between population means i.e = 2 ( given in the question)
b) The standard deviation of the sampling distribution of X`1- X`2 ( standard error of X`1- X`2) denoted by σ_X`1- X`2 is given by
σ_X`1- X`2 = √σ²/n1 +σ²/n2
Var ( X`1- X`2) = Var X`1 + Var X`2 = σ²/n1 +σ²/n2
so
σ_X`1- X`2 =√20 +20 = 6.324
if the populations are normal the sampling distribution X`1- X`2 , regardless of sample sizes , will be normal with mean u1-u2 and variance σ²/n1 +σ²/n2.
Where as Z is normally distributed with mean zero and unit variance.
If we take X`1- X`2= 0 and u1-u2= 2 and standard deviation of the sampling distribution = 6.324 then
Z= 0-2/ 6.342= -0.31625
P(-0.31625<z<0)= 0.1217
The probability would be 0.1217
