A I think is correct, but you may want to get a second opinion.
Answer:
it's potential energy decreases
Answer:

Step-by-step explanation:
So we want to make x the subject of the formula:

First, distribute the left side:

Combine all the terms with x with it on one side. To do this, first subtract bx from both sides. The right side cancels:

Remove the -ab from the left. Add ab to both sides. The left side cancels:

Now, distribute out the x from the left side:

Divide both sides by (a-b). The left side cancels:

Therefore:

The scientist would use milligrams, grams, and kilograms.
The best procedure would be to randomly pick 52 fish from the entire pond and weigh each of them as this would be the most unbiased way to achieve the average mass