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Svetllana [295]
3 years ago
14

Focus (-3,3) vertex (0,3). What is the equation for the parabla

Mathematics
1 answer:
Gwar [14]3 years ago
8 0

Answer:

(y - 3)² = 12(x + 3)  

Step-by-step explanation:

The focus is to the right of the vertex, so the parabola is sideways and opens to the right.

The conic form of a sideways parabola is

(y - k)² = 4p(x - h)

The vertex is at h = -3; k = 3

The focus is at (h + p, k) = (-3 + p, 3)

The vertex and focus are three units apart, so p = 3.

The equation of your parabola is

(y - 3)² = 12(x + 3)

The figure below shows the graph of your parabola with its focus and vertex.

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The solutions to the given inequalities are x < 6 OR x < -10

<h3>Linear Inequalities </h3>

From the question, we are to solve the given inequalities

The given inequalities are

6x - 4(2x - 5) > 8 or 5x + 9 < 2x - 21

First solve,

6x - 4(2x - 5) > 8

Clear the bracket

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Divide both sides by -2 and flip the sign,

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For,

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Subtract 2x from both sides

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Divide both sides by 3

3x/3 < -30/3

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Hence, the solutions to the given inequalities are x < 6 OR x < -10

Learn more on Inequalities here: brainly.com/question/246993

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