****BRAINLIEST GOES TO THE FIRST CORRECT ANSWER****

Brandon has 32 stamps. he wants to display the stamps in rows,with the same n

AleksandrR [38]

Okay, let's work this out...
What we know:
-32 stamps in all
- rows (horizontal)
- same # in each
What we "want to know" :
- # of combinations (different)
Problem Solving :
This is actually very easy its just the words than get ya!
1st : we need to figure out the factors of 32...
In other words, we need to figure out _x_=32 and how many different combinations and ways there are!
Note:(* means multiplication)
#1: What are the factors of 32?
32: 1*32 , 2*16 , 4*8
32: 32*1 , 16*2 , 8*4
The factors (not including 1 are 2,4,8,16)
Now, as you can see, there are 4 ways to get 32 as shown first.
||||||||||||||||
||||||||||||||||
^
That ¦ is 1 way with 16 in 2 rows. Basic multiplication, 16*2=32 or 16+16=32.
But, this is also a way,
||
||
||
||
||
||
||
||
||
||
||
||
||
||
||
||
Now there should be 2 in each row and 16 rows. Again 2*16=32 or 2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2=32
That's two ways so far.
||||||||
||||||||
||||||||
||||||||
Another way which is 4 rows with 8 in each.
4*8=32 or 8+8+8+8=32
But, this is also a way,
||||
||||
||||
||||
||||
||||
||||
||||
Now that is 8 rows with 4 in each. 8*4=32 or 4+4+4+4+4+4+4+4=32
That was our fourth way.
Again NOT including 1. If you include 1 then there will be 6 ways but aside from that there are 4 ways.
I hope that helped I worked hard typing this all for you. Any questions just ask!

3 0

3 years ago

If eight trash bags last for thirty days then how many trash bags do you need for 180 days

34kurt

Let's Just See How Many Times 30 Goes Into 180

$\frac{180}{30} = 6$
Since 8 trash bags last 30 days, let's multiply

$6 \times 8 = 48 \: bags$
ANSWER

You'll Need 48 Trash Bags For 180 Days

5 0

3 years ago

Read 2 more answers

How do I solve for AB? (rounded to the nearest tenth)

kolbaska11 [484]

Answer:

The answer would be 8.1

Step-by-step explanation:

For the smaller triangle, you use the pythagorean theorem. a squared + b squared = c squared.

To find one of the legs, you do 5 squared - 3 squared = b squared.

25 - 9 = b squared. (BD)

16 = b squared

4 = b

Now for the bigger right triangle. You still use the same tactic.

7 squared + 4 squared = c squared (which is AB)

49 + 16 = c squared

65 = c squared

That means c would equal: square root of 65, which is 8.0622577483 which rounds to 8.1

7 0

2 years ago

Complete the square and write in standard form. Show all work.What would be the conic section:CircleEllipseHyperbolaParabola

mote1985 [20]

ANSWER

This is an ellipse. The equation is:

$\frac{(x-1)^2}{3^2}+\frac{(y+4)^2}{4^2}=1$

EXPLANATION

We have to complete the square for each variable. To do so, we have to take the first two terms and compare them with the perfect binomial squared formula,

$(a+b)^2=a^2+2ab+b^2$

For x we have to take 16x² and -32x. Since the coefficient of x is not 1, first, we have to factor out the coefficient 16,

$16x^2-32x=16(x^2-2x)$

Now, the first term of the expanded binomial would be x and the second term -2x. Thus, the binomial is,

$(x-1)^2=x^2-2x+1$

To maintain the equation, we have to subtract 1,

$16(x^2-2x+1-1)=16((x-1)^2-1)=16(x-1)^2-16$

Now, we replace (16x² - 32x) from the given equation by this equivalent expression,

$16(x-1)^2-16+9y^2+72y+16=0$

The next step is to do the same for y. We have the terms 9y² + 72y. Again, since the coefficient of y² is not 1, we factor out the coefficient 9,

$9y^2+72y=9(y^2+8y)$

Following the same reasoning as before, we have that the perfect binomial squared is,

$(y+4)^2=y^2+8y+16$

Remember to subtract the independent term to maintain the equation,

$9(y^2+8y)=9(y^2+8y+16-16)=9((y+4)^2-16)=9(y+4)^2-144$

And now, as we did for x, replace the two terms (9y² + 72y) with this equivalent expression in the equation,

$16(x-1)^2-16+9(y+4)^2-144+16=0$

Add like terms,

$\begin{gathered} 16(x-1)^2+9(y+4)^2+(-16-144+16)=0 \\ 16(x-1)^2+9(y+4)^2-144=0 \end{gathered}$

Add 144 to both sides,

$\begin{gathered} 16(x-1)^2+9(y+4)^2-144+144=0+144 \\ 16(x-1)^2+9(y+4)^2=144 \end{gathered}$

As we can see, this is the equation of an ellipse. Its standard form is,

$\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1$

So the next step is to divide both sides by 144 and also write the coefficients as fractions in the denominator,

$\begin{gathered} \frac{16(x-1)^2}{144}+\frac{9(y+4)^2}{144}=\frac{144}{144} \\ \\ \frac{(x-1)^2}{\frac{144}{16}}+\frac{(y+4)^2}{\frac{144}{9}}=1 \end{gathered}$

Finally, we have to write the denominators as perfect squares, so we identify the values of a and b. 144 is 12², 16 is 4² and 9 is 3²,