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Alex Ar [27]
3 years ago
6

Connor bought a baseball card eight years ago that has depreciated (goes down in value) by $120 since he purchased it. Find the

average yearly change in the value of the card.
and show me how did you do it
Mathematics
2 answers:
Vesna [10]3 years ago
8 0

Answer:

$120/8= $15 in a year.

15 times 8 is 120.

<u>My Work:</u>

You can go to google and type in 120/8

Flura [38]3 years ago
6 0

Answer:

-$15

Step-by-step explanation:

To find the average yearly change, divide -120 by 8, since it has decreased by $120 over 8 years.

-120/8

= -15

So, the average yearly change in the value of the card is -$15

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3/5 = 0.3 * x
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So to solve it...
3/5 = 0.3x
x = 3/5 ÷ 0.3 = 2
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Ashley has 500 songs in his music player. Every week he adds 10 songs to his collection. How many songs will he have in his musi
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500 (the current collection) + 10 (the weekly addition) x 20 (weeks to add)

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500+200

700
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The decimal is 0.9 and the fraction is 9/10
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La sociedad de ex alumnos de una escuela organizó el año pasado una posada a la que asistieron 420 personas. A la posada de este
MariettaO [177]

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Step-by-step explanation:

5 0
3 years ago
Determine whether the alternating series E (-1)^n+1 (n/8)^n converges or diverges. Choose the correct answer below​ and, if​ nec
RUDIKE [14]

Answer:

C

Step-by-step explanation:

Solution:-

- The Alternate series test is applicable for alternating series with has terms summed and subtracted alternatively and takes the form of:

       

                                   ∑ an

Were,

                                a_n = ( -1 ) ^(^n^+^1^) b_n

- Where, {  bn } > 0 for all n. Then if the following conditions are met:

1. Lim ( n -> ∞ ) { b_n } = 0

2. b ( n + 1 )  < bn  .... bn is a decreasing function.

Conclusion:- The series { ∑ an } is convergent.

- The following series is given as follows:

                                ∑  ( - 1 )^(^n^+^1^) (\frac{n}{8} )^n

Where,

                               b_n = (\frac{n}{8} )^n

1 . We will first test whether the sequence { bn } is decreasing or not. Hence,

                              b_n_+_1 - b_n < 0\\\\(\frac{n+1}{8})^(^n^+^1^) - (\frac{n}{8})^n\\\\(\frac{n}{8})^n ( \frac{n-7}{8} ) \\\\

We see that for n = 1 , 2 , 3 ... 6 the sequence { b_n } is decreasing; however, for n ≥ 7 the series increases. The condition is not met for all values of ( n ). Hence, the Alternating series test conditions are not satisfied.

We will now apply the root test that states that a series given in the following format:

                               ∑ an

- The limit of the following sequence { an } is a constant ( C ).

                               C = Lim ( n - > inf ) [ a_n ] ^\frac{1}{n} \\\\

1. C < 1 , The series converges

2.C > 1 , The series diverges

3. C = 1 , test is inconclusive

- We will compute the limit specified by the test as follows:

                          Lim ( n - >inf ) = [ (\frac{n}{8})^n ]^\frac{1}{n}   \\\\Lim ( n - >inf ) = [ (\frac{n}{8}) ] = inf   \\\\

- Here, the value of C = +∞ > 1. As per the Root test limit conditions we see that the series { ∑ an } diverges.

Note: Failing the conditions of Alternating Series test does not necessarily means the series diverges. As the test only implies the conditions of "convergence" and is quiet of about "divergence". Hence, we usually resort to other tests like { Ratio, Root or p-series tests for the complete picture }.

8 0
3 years ago
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