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vovangra [49]
3 years ago
9

Considering the graph of a line with a negative slope, which of the following could be true? Check all that apply

Mathematics
2 answers:
-Dominant- [34]3 years ago
7 0

Answer:B,D,E

Step-by-step explanation:

Per a.p.e.x

Mandarinka [93]3 years ago
4 0

Answer:

Step-by-step explanation:

The following statements are true:

B. As the absolute value of the negative slope gets smaller, the

graph of the line gets less steep.

E. The line goes down from left to right.

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In the number 7725 which place contain digits where one digit is ten times as great as the other
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Find the area of each regular polygon. Round to the nearest tenth.
miskamm [114]

Given:

A regular polygon with three vertices and side 14 cm.

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The area of an equilateral triangle is:

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Solve sin x - (3sin x-1) = 0
soldi70 [24.7K]

Answer:

\large\boxed{x=\dfrac{\pi}{6}+2k\pi\ \vee\ x=\dfrac{5\pi}{6}+2k\pi,\ k\in\mathbb{Z}}

Step-by-step explanation:

\sin x-(3\sin x-1)=0\\\\\sin x-3\sin x+1=0\qquad\text{subtract 1 from both sides}\\\\-2\sin x=-1\qquad\text{divide both sides by 2}\\\\\sin x=\dfrac{1}{2}\Rightarrow x=\dfrac{\pi}{6}+2k\pi\ \vee\ x=\dfrac{5\pi}{6}+2k\pi,\ k\in\mathbb{Z}

\text{Equation:}\\\\\sin x=a\\\\\text{has solutions}\\\\x=\theta+2k\pi\ \vee\ x=(\pi-\theta)+2k\pi\\\\\text{Why}\ 2k\pi?\\\text{Because the sine function has a period of}\ 2\pi.

\text{look at the table}\\\\\sin x=\dfrac{1}{2}\to x=\dfrac{\pi}{6}\ \vee\ x=\pi-\dfrac{\pi}{6}=\dfrac{5\pi}{6}

\text{Other solution:}\\\\\sin x=\dfrac{1}{2}\Rightarrow x=\sin^{-1}\dfrac{1}{2}\\\\x=\dfrac{\pi}{6}+2k\pi\ \vee\ x=\dfrac{5\pi}{6}+2k\pi

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3 years ago
Choose the correct solution set. [x – 1] > 6​
Tanya [424]
The correct answer is [x-1and get;6
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3 years ago
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