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lana66690 [7]
3 years ago
5

Can someone help me with this question please?

Mathematics
1 answer:
gladu [14]3 years ago
4 0
X-intercept is (1.2,0)
y-intercept is (0,-1.5)
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Can someone help me with these 4 geometry questions? Pls it’s urgent, So ASAP!!!!
blagie [28]

<u>Question 4</u>

1) \overline{BD} bisects \angle ABC, \overline{EF} \perp \overline{AB}, and \overline{EG} \perp \overline{BC} (given)

2) \angle FBE \cong \angle GBE (an angle bisector splits an angle into two congruent parts)

3) \angle BFE and \angle BGE are right angles (perpendicular lines form right angles)

4) \triangle BFE and \triangle BGE are right triangles (a triangle with a right angle is a right triangle)

5) \overline{BE} \cong \overline{BE} (reflexive property)

6) \triangle BFE \cong \triangle BGE (HA)

<u>Question 5</u>

1) \angle AXO and \angle BYO are right angles, \angle A \cong \angle B, O is the midpoint of \overline{AB} (given)

2) \triangle AXO and \triangle BYO are right triangles (a triangle with a right angle is a right triangle)

3) \overline{AO} \cong \overline{OB} (a midpoint splits a segment into two congruent parts)

4) \triangle AXO \cong \triangle BYO (HA)

5) \overline{OX} \cong  \overline{OY} (CPCTC)

<u>Question 6</u>

1) \angle B and \angle D are right angles, \overline{AC} bisects \angle BAD (given)

2) \overline{AC} \cong \overline{AC} (reflexive property)

3) \angle BAC \cong \angle CAD (an angle bisector splits an angle into two congruent parts)

4) \triangle BAC and \triangle CAD are right triangles (a triangle with a right angle is a right triangle)

5) \triangle BAC \cong \triangle DCA (HA)

6) \angle BCA \cong \angle DCA (CPCTC)

7) \overline{CA} bisects \angle ACD (if a segment splits an angle into two congruent parts, it is an angle bisector)

<u>Question 7</u>

1) \angle B and \angle C are right angles, \angle 4 \cong \angle 1 (given)

2) \triangle BAD and \triangle CAD are right triangles (definition of a right triangle)

3) \angle 1 \cong \angle 3 (vertical angles are congruent)

4) \angle 4 \cong \angle 3 (transitive property of congruence)

5) \overline{AD} \cong \overline{AD} (reflexive property)

6) \therefore \triangle BAD \cong \triangle CAD (HA theorem)

7) \angle BDA \cong \angle CDA (CPCTC)

8) \therefore \vec{DA} bisects \angle BDC (definition of bisector of an angle)

8 0
1 year ago
Help please
Ede4ka [16]

Answer: A: 1524 miles B: Average is 508 mph

Step-by-step explanation: Add the miles on the picture to get the total amount of miles traveled (1524) and then divide by 3 hours to get 508 mph.

Hope this helped!

Mark Brainliest if you want!

4 0
3 years ago
To find the distance across a lake, a
Nesterboy [21]

The distance across the lake, a is 611 yards

<h3>Right angle triangle:</h3>

Right angle triangle have one of its angles as 90 degrees. Therefore, the side a can be found using trigonometric ratios,

Therefore,

tan 47° = opposite / adjacent

tan 47° = a / 570

cross multiply

a = 570 tan 47°

a = 570 × 1.07236871002

a = 611.250164714

a = 611 yards

learn more on right triangle here: brainly.com/question/18450490

6 0
2 years ago
Read 2 more answers
Please help me asap :) thank you
Mashutka [201]

Answer:

1 1/2 points

Step-by-step explanation:


3 0
3 years ago
Which system is the solution of the graph?<br> HELPPPP
ankoles [38]
To solve a system of linear equations graphically we graph both equations in the same coordinate system. The solution to the system will be in the point where the two lines intersect. The two lines intersect in (-3, -4) which is the solution to this system of equations
3 0
3 years ago
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