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kiruha [24]
2 years ago
13

Brian bought a new air conditioning unit on his credit card. The unit had a base price of $435. Brian made no other purchases on

his credit card. Brian’s credit card has an interest rate of 9.4%, compounded monthly, and Brian paid off the balance by making monthly payments for a year and a half. If the sales tax in Brian’s area is 8.51%, how much did Brian pay in total? (Round all dollar values to the nearest cent.)
a.
$472.02
b.
$468.00
c.
$496.32
d.
$507.96
Mathematics
1 answer:
Svetlanka [38]2 years ago
3 0

Answer:

D is the correct answer

Step-by-step explanation:

Given:

Unit base price: $435

Credit Card interest rate, i = 9.4% compounded monthly; i = 0.00783/month comp monthly

n = 1.5 years = 18 months

sales tax = 8.51%

First, determine the actual price of the unit by adding the sales tax to the base price of the unit:

$435 * (1 + 0.0851)

Actual price = $472.0185

So, the total amount paid by Brian should be higher than the actual price since he used his credit card. Use the formula from economics:

F = P (1+i)^n

F = $507.96

Therefore, the total amount paid by Brian is $507.96.

(Hope this helps can I pls have brainlist (crown) ☺️)

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A new shopping mall is considering setting up an information desk manned by one employee. Based upon information obtained from s
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Answer:

a) P=1-\frac{\lambda}{\mu}=1-\frac{20}{30}=0.33 and that represent the 33%

b) p_x =\frac{\lambda}{\mu}=\frac{20}{30}=0.66

c) L_s =\frac{20}{30-20}=\frac{20}{10}=2 people

d) L_q =\frac{20^2}{30(30-20)}=1.333 people

e) W_s =\frac{1}{\lambda -\mu}=\frac{1}{30-20}=0.1hours

f) W_q =\frac{\lambda}{\mu(\mu -\lambda)}=\frac{20}{30(30-20)}=0.0667 hours

Step-by-step explanation:

Notation

P represent the probability that the employee is idle

p_x represent the probability that the employee is busy

L_s represent the average number of people receiving and waiting to receive some information

L_q represent the average number of people waiting in line to get some information

W_s represent the average time a person seeking information spends in the system

W_q represent the expected time a person spends just waiting in line to have a question answered

This an special case of Single channel model

Single Channel Queuing Model. "That division of service channels happen in regards to number of servers that are present at each of the queues that are formed. Poisson distribution determines the number of arrivals on a per unit time basis, where mean arrival rate is denoted by λ".

Part a

Find the probability that the employee is idle

The probability on this case is given by:

In order to find the mean we can do this:

\mu = \frac{1question}{2minutes}\frac{60minutes}{1hr}=\frac{30 question}{hr}

And in order to find the probability we can do this:

P=1-\frac{\lambda}{\mu}=1-\frac{20}{30}=0.33 and that represent the 33%

Part b

Find the proportion of the time that the employee is busy

This proportion is given by:

p_x =\frac{\lambda}{\mu}=\frac{20}{30}=0.66

Part c

Find the average number of people receiving and waiting to receive some information

In order to find this average we can use this formula:

L_s= \frac{\lambda}{\lambda -\mu}

And replacing we got:

L_s =\frac{20}{30-20}=\frac{20}{10}=2 people

Part d

Find the average number of people waiting in line to get some information.

For the number of people wiating we can us ethe following formula"

L_q =\frac{\lambda^2}{\mu(\mu-\lambda)}

And replacing we got this:

L_q =\frac{20^2}{30(30-20)}=1.333 people

Part e

Find the average time a person seeking information spends in the system

For this average we can use the following formula:

W_s =\frac{1}{\lambda -\mu}=\frac{1}{30-20}=0.1hours

Part f

Find the expected time a person spends just waiting in line to have a question answered (time in the queue).

For this case the waiting time to answer a question we can use this formula:

W_q =\frac{\lambda}{\mu(\mu -\lambda)}=\frac{20}{30(30-20)}=0.0667 hours

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