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4 years ago

Which of the following is the midsegment for A ACE?

Mathematics

1 answer:

11111nata11111 [884]4 years ago

5 0

Answer:

A. DB

Step-by-step explanation:

The line BD is the mid segment because it connects the midpoints of line segment AC and CE

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What is the equation of a line through point (-4,5) that is perpendicular

OLEGan [10]

Answer:

set two equation of line y=ax+b and y=cx+d

when these two lines are perpendicular to each other, then a*c=(-1)

set answer is y=ax+b

we can know that a=1/6

bring in a=1/6 and(-4,5)

5=(1/6)*(-4)+b

=>5=(-2/3)=b

=>b=5 2/3

answer is y=(1/6)x+5 2/3

4 0

3 years ago

What is the average speed that robin mus drive to reach her friend's house 170 miles away in 2 1/2 hr

Tamiku [17]

68 miles / hour

Average speed = distance / time

distance = 170 and time = 5/2 ( as an improper fraction)

speed = 170 ÷ $\frac{5}{2}$ = 170 × $\frac{2}{5}$ = $\frac{340}{5}$ = 68

4 0

3 years ago

Read 2 more answers

Find the mesurement of the angle?

nevsk [136]

Answer:

100

Step-by-step explanation:

if both sides are the same then you can mirror the angles only if there equal

5 0

3 years ago

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Theorem: A line parallel to one side of a triangle divides the other two proportionately.

Elenna [48]

Answer:

Segment BF = 16 is true.

Step-by-step explanation:

Since, DE is parallel to BC, so DE will divide AB and AC proportionally.

Hence,

$\frac{AE}{EC} = \frac{AD}{DB}$

⇒ $\frac{12}{18} = \frac{6}{DB}$

{Since, given that AE = 12, EC = 18 and AD = 6}

⇒ BD = 9.

Again, since, EF is parallel to AB, so EF will divide BC and AC proportionally.

Hence, $\frac{CE}{AE} = \frac{FC}{BF}$

⇒ $\frac{18}{12} = \frac{24}{BF}$

{Since, given that AE = 12, EC = 18 and FC= 24}

⇒ BF = 16.

Therefore, segment BF = 16 is true. (Answer)

3 0

3 years ago

Solve the system of linear equations. <br> −8x+5y=26<br> 9x−3y=−3

Sloan [31]

Answer: x = 3 and y = 10

Step-by-step explanation:

-8x + 5y = 26 .................. equation 1

9x - 3y = -3 ................ equation 2

Solving the system of linear equations by elimination method.

The means we have to make the coefficient of one of the variable the same in order to eliminate the variable first.

Let us eliminate the variable y first , this means we will multiply equation 1 by 3 and multiply equation 2 by 5. Doing this , we have

-24x + 15y = 78 ............. equation 3

45x - 15y = -15 ................ equation 4

Now that we have the same coefficient , we have to check their signs , if the have the same signs , we will subtract , that is , if both are having positive signs , we will subtract , if both have negative signs , we will also subtract but if their signs differ we will add. Following this rule and considering the equations above , the coefficients of y have different signs , so we will add equation 3 and equation 4 , so we have:

21x = 63

x = 63/21

x = 3

Substitute x = 3 into equation 1 or equation 2 to get the value of y , using equation 2 , we have

9x - 3y = -3

9(3) - 3y = -3

27 - 3y = -3

27+3 = 3y

30 = 3y

30/3 = y

Therefore y = 10

Therefore : x = 3 and y = 10

8 0

4 years ago