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sesenic [268]
3 years ago
12

Solve 24x + 2y = 48 for x

Mathematics
2 answers:
trapecia [35]3 years ago
5 0
<span>Simplifying 24x + 2y = 48.  Solving 24x + 2y = 48.
  Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right.
 Add '-2y' to each side of the equation.
 24x + 2y + -2y = 48 + -2y.
  Combine like terms: 2y + -2y = 0 24x + 0 = 48 + -2y 24x = 48 + -2y.
  Divide each side by '24'.
x = 2 + -0.08333333333y Simplifying x = 2 + -0.08333333333y</span>
drek231 [11]3 years ago
3 0
Isolate x.
24x = 48 - 2y

Divide by 24.
x = 2 - y/12
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Answer:

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But we need to calculate the mean with the following formula:

\bar X = \frac{\sum_{i=1}^n X_I}{n}

And replacing we got:

\bar X = \frac{ 1.04+1.00+1.13+1.08+1.11}{5}= 1.072

And for the sample variance we have:

s^2 = \frac{(1.04-1.072)^2 +(1.00-1.072)^2 +(1.13-1.072)^2 +(1.08-1.072)^2 +(1.11-1.072)^2}{5-1}= 0.00277\ approx 0.003

And thi is the best estimator for the population variance since is an unbiased estimator od the population variance \sigma^2

E(s^2) = \sigma^2

Step-by-step explanation:

For this case we have the following data:

1.04,1.00,1.13,1.08,1.11

And in order to estimate the population variance we can use the sample variance formula:

s^2 = \frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}

But we need to calculate the mean with the following formula:

\bar X = \frac{\sum_{i=1}^n X_I}{n}

And replacing we got:

\bar X = \frac{ 1.04+1.00+1.13+1.08+1.11}{5}= 1.072

And for the sample variance we have:

s^2 = \frac{(1.04-1.072)^2 +(1.00-1.072)^2 +(1.13-1.072)^2 +(1.08-1.072)^2 +(1.11-1.072)^2}{5-1}= 0.00277\ approx 0.003

And thi is the best estimator for the population variance since is an unbiased estimator od the population variance \sigma^2

E(s^2) = \sigma^2

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zysi [14]

Answer:

Number of student bring their lunch = 60

Step-by-step explanation:

Given:

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3 0
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