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amm1812
2 years ago
8

RJ has two loans. Loan H has a nominal rate of 5.68%, compounded daily. Loan I has a nominal rate of 6.33%, compounded monthly.

Which loan's effective rate had the greater increase, relative to its nominal rate, and how much greater is its increase than that of the other loan?
a.
Loan I’s increase was 0.03 percentage points greater than Loan H’s.
b.
Loan I’s increase was 0.68 percentage points greater than Loan H’s.
c.
Loan H’s increase was 0.16 percentage points greater than Loan I’s.
d.
Loan H’s increase was 0.49 percentage points greater than Loan I’s.
Mathematics
1 answer:
Naily [24]2 years ago
6 0

Answer:

The correct answer for this question is:

The loan's effective rate that had the greater increase, relative to its nominal rate, and how much greater is its increase than that of the other loan is that 'loan H’s increase was 0.16 percentage points greater than Loan I’s.

Step-by-step explanation:

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Step-by-step explanation:

Total = 45

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Rzqust [24]

Answer:

\frac{180}{147}

Step-by-step explanation:

  • Simplify (\frac{3}{-7} - \frac{11}{21} )

=> \frac{(-3 \times 3) - 11}{21}

=> \frac{-9 - 11}{21}

=> \frac{-20}{21}

  • Find the additive inverse of  \frac{-20}{21} by using its property - <em>"Sum of a number & its additive inverse is always zero". </em>Assume that 'x' is an additive inverse of  \frac{-20}{21}.

=> x + \frac{-20}{21} = 0

=> x = 0 - (-\frac{20}{21}) = \frac{20}{21}

  • Simplify (\frac{9}{5} \div \frac{7}{5} )

=> \frac{9}{5} \times \frac{1}{\frac{7}{5} }

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=> \frac{180}{147}

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3 years ago
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