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kap26 [50]
3 years ago
6

What mass of NaNO3 is needed to make 3.5 L of 2.2 M solution? (Na = 23.0g, N=14.0g, O=16.0g)

Chemistry
1 answer:
olganol [36]3 years ago
8 0

Answer:

= 654.5 g NaNO3

Explanation:

Molarity = Moles/ volume

Volume = 3.5 L

Molarity = 2.2 M

Therefore;

Moles = Molarity × volume

          = 3.5 L × 2.2 M

          = 7.7 moles

But 1 mole of NaNO3 is 85 g/mol

Mass of NaNO3 = 85 g/mole × 7.7 moles

                          = 654.5 g NaNO3

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Which has a higher kinetic energy an object at 20° C or an object at 50°C
Simora [160]

Answer:

The object at 50°C will have a higher kinetic energy.

Explanation:

Temperature is a measure of the average kinetic energy of the particles in an object. As you introduce more energy into the system (e.g. heat the object), the particles on average move faster because they have more kinetic energy.

5 0
3 years ago
How many moles are in 24.75 g of H2O? What is given the conversation and the unknown?
riadik2000 [5.3K]

Answer:

1.373 mol H₂O

General Formulas and Concepts:

<u>Chemistry - Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

24.75 g H₂O

<u>Step 2: Identify Conversions</u>

Molar Mass of H - 1.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol

<u>Step 3: Convert</u>

<u />24.75 \ g \ H_2O(\frac{1 \ mol \ H_2O}{18.02 \ g \ H_2O} ) = 1.37347 mol H₂O

<u>Step 4: Check</u>

<em>We are given 4 sig figs. Follow sig fig rules and round.</em>

1.37347 mol H₂O ≈ 1.373 mol H₂O

7 0
3 years ago
Which factor is generally responsible for high melting points?
vlabodo [156]

A. High intermolecular forces of attraction. If there are high intermolecular forces, the molecules will need large energies to escape into the liquid. The substance will nave a high melting point.

The other options are <em>incorrect </em>because they are <em>weak force</em>s. They would cause <em>low melting points</em>.

7 0
3 years ago
Read 2 more answers
When 12 moles of methanol (ch3oh) and 24 moles of oxygen gas react according to the chemical equation below, what is the limitin
Nataliya [291]
The balanced reaction equation for the reaction between CH₃OH and O₂ is 
                        2CH₃OH(l) + 3O₂(g) → 2CO₂(g) + 4H₂O(l)
Initial moles        12                24
Reacted moles   12                18
Final moles          -                   6              12               24
 
The stoichiometric ratio between CH₃OH and O₂ is 2 : 3
Hence,
   reacted moles of O₂ = reacted moles of CH₃OH x (3/2)
                                      = 12 mol x 3 / 2  
                                      = 18 mol

All of CH₃OH moles react with O₂.

Hence, the limiting agent is CH₃OH. 

Excess reagent is O₂.
Amount of moles of excess reagent left = 24 - 18 mol = 6 mol
                                            
5 0
4 years ago
Help what is a b c please I want help this my quiz quick
stich3 [128]

Answer:

1.

A= <u>sum</u><u>(</u><u>mass</u><u>*</u><u>percent</u><u> </u><u>abundance</u><u>)</u>

M 100

=(23.985*78.70)+(24.946*10.13)+(25.983*11.17)/100

= 24.3

2. The element is Magnesium.

3. 2412Mg,2512Mg and 2612Mg

4 0
3 years ago
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