Times 2/3 by 6 and you get 4
Answer:
yes
Step-by-step explanation:
Answer:
Option B is not a justification
Step-by-step explanation:
Option A is a justification (to get two pair of similar triangles (ABC-ACD) and (ABC-BCD))
Option C is a justification (a^2 = cy, b^2 = cx, a^2 + b^2 = cy + cx)
Option D is a justification (a^2 + b^2 = cy + cx = c(y + x) = c^2)
=> Option B is not a justification
F(x)=x^2+2x+1 & g(x)=3(x+1)^2
now, f(x)+g(x)
=x^2+2x+1+3(x+1)^2
=x^2+2x+1+3(x^2+2x+1)
=x^2+2x+1+3x^2+6x+3
=4x^2+8x+4<===answer(c)
next:
f(x)=x^2-1 & g(x)=x+3
now, f(g(x))=(x+3)^ -1
=x^2+6x+9-1
=x^2+6x+8<====answer(b)
i solve two of ur problems.
now try the 3rd one that is similar to no. 1
and try the last two urself.
Answer:
321
Step-by-step explanation:
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