1 3 4
1 -- + 1 -- = 2 --
5 5 5
Explanation:
1 + 1 = 2
1/5 + 3/5 = 4/5<span />
If in the triangle ABC , BF is an angle bisector and ∠ABF=41° then angle m∠BCE=8°.
Given that m∠ABF=41° and BF is an angle bisector.
We are required to find the angle m∠BCE if BF is an angle bisector.
Angle bisector basically divides an angle into two parts.
If BF is an angle bisector then ∠ABF=∠FBC by assuming that the angle is divided into two parts.
In this way ∠ABC=2*∠ABF
∠ABC=2*41
=82°
In ΔECB we got that ∠CEB=90° and ∠ABC=82° and we have to find ∠BCE.
∠BCE+∠CEB+EBC=180 (Sum of all the angles in a triangle is 180°)
∠BCE+90+82=180
∠BCE=180-172
∠BCE=8°
Hence if BF is an angle bisector then angle m∠BCE=8°.
Learn more about angles at brainly.com/question/25716982
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Answer:
idk
Step-by-step explanation:
idk just responding
for points
I hope this helps you
x^2+4x+3=2x+6
x^2+2x-3 =0
x +3
x -1
(x+3)(x-1)=0
x+3=0 x= -3
x-1=0 x=1
