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Mashutka [201]
3 years ago
9

How to prove using basic definitions, If xy=xz then y=z

Mathematics
2 answers:
Zinaida [17]3 years ago
7 0
Division. The x is divided from both sides.
velikii [3]3 years ago
4 0
Yep think of scales what you take from one side take from the other
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4(2x + 3) ÷ 5y From the expression above, provide an example of each of the following: sum, term, product, factor, quotient, and
Ann [662]

Answer:

Sum - 2x + 3

term - 2x

Product - 4(2x + 3)

Factor - not present

quotient - (2x + 3) / 5

Coeffecient - 4(2x + 3)

I really hope this helps

6 0
2 years ago
Read 2 more answers
The questions on a test consist of 10 multiple choices, 3 essays, and 9 free responses. If the questions are ordered randomly, w
stepladder [879]

Answer:

\frac{9}{22}

Step-by-step explanation:

add all qestions together 10+3+9=22

and put the number of free responces on top of the total number of qestions

\frac{9}{22\\}

and you cant simplify it so its in its simplist form

3 0
2 years ago
2/9 of the students in a school are in sixth grade.
IRISSAK [1]

There are 20 students in sixth grade

Step-by-step explanation:

  • Step 1: Find the number of sixth-graders in the school.

Total number of students = 90

Number of sixth-graders = 2/9 of total students

⇒ Number of 6th graders = 2/9 × 90 = 20 students

5 0
2 years ago
Read 2 more answers
Solve for the given variable 3(2x+5)=4x+21
Nookie1986 [14]

Answer:

x=3

Step-by-step explanation:

3(2x+5)=4x+21

6x+15=4x+21

-4x            -4x

2x+15= 21

     -15    -15

2x=6

2     2

<h2>x=3                          Hope that helped!!!!</h2>
6 0
3 years ago
The city of Omaha decided to build a new parking garage in hopes of luring more people to the Old Market district.The city will
dimulka [17.4K]

Answer:

Given:

Mean, u = 135

Sample size, n = 42

Sample mean, x' = 126

Standard deviation = 16

Significance level = 0.05

1) The null and alternative hypotheses:

H0 : u = 135 (the revenue per day is $135)

H1 : u < 135 (the revenue per day is less than $135)

2) In this case, we have a left tailed test.

Let's use the formula:

= \frac{x' - u}{s/ \sqrt{n}} = \frac{126 - 135}{16 / \sqrt{42}} = -3.645

t = - 3.645

Critical value: at a significance level of 0.05, left tailed test,

tcritical = -1.683

We reject null hypothesis, H0, since t calculated, -3.645 is less than tcritical, -1.683.

3) Given, a = 0.05, df = 41, left tailed test,

t-value = 2.02

For the corresponding confidence interval, we have:

CI = (x' - \frac{t * \sigma}{\sqrt{n}}, x' + \frac{t * \sigma}{\sqrt{n}})

CI = (126 - \frac{2.02 * 16}{\sqrt{42}}, 126 + \frac{2.02 * 16}{\sqrt{42}})

CI = (121.014, 130.986)

4) Conclusion:

We reject the estimated potential revenue advised by the consultant, H0, as it is too high, because the t-calculated falls in rejection region(i.e, less than critical value), also the upper limit of the confidence interval is less than $135.

5 0
2 years ago
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