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3 years ago

12

Given that f(x)=2x-1, find f(3)

1 answer:

Dennis_Churaev [7]3 years ago

7 0

Answer:

5

Step-by-step explanation:

Put 3 where x is and do the arithmetic.

f(x) = 2x -1

f(3) = 2·3 -1 = 6-1

f(3) = 5

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In geometry a train metal tracks and Wooden ties would be Parrell, Skew, perpendicular or none??

Nadusha1986 [10]

Answer: They would be Parrellel

Step-by-step explanation:

7 0

3 years ago

Solve the following equation: |7 – (24 ÷ | 3-6 |)|<br>(A)15(B)-12(C)1(D)-1

Zepler [3.9K]

PEDMAS

The rule is Paranthesis First

|7-(24÷|3-6|)|

|7-(24÷|-3|)|

Now we have to get the -3 outside the 2 Lines but the lines are saying that if the number inside is negative when you get it outside it has to be positive.

|7-(24÷3)|-

|7-(8)|

|7-8|

|-1|

= 1

3 0

3 years ago

Read 2 more answers

A car starts with a dull tank of gas. After driving around 5he city, 1/7 of the gas has been used. With the rest of the gas in t

Sati [7]

Answer:

$\frac{2}{7}$

Step-by-step explanation:

Given:

A car starts with a dull tank of gas

1/7 of the gas has been used around the city.

With the rest of the gas in the car, the car can travel to and from Ottawa three times.

Question asked:

What fractions of a tank of gas does each complete trip to Ottawa use?

Solution:

Fuel used around the city = $\frac{1}{7}$

Remaining fuel after driving around the city = 1 - $\frac{1}{7}$

= $\frac{7 - 1}{7} = \frac{6}{7}$

According to question:

As from the rest of the gas in the car that is $\frac{6}{7}$ , the car can complete 3 trip to Ottawa which means,

By unitary method:

The car can complete 3 trip by using = $\frac{6}{7}$ tank of gas.

The car can complete 1 trip by using = $\frac{6}{7} \div 3$

= $\frac{6}{7} \times\frac{1}{3}$

= $\frac{6}{21}$

= $\frac{2}{7}$ tank of gas

Thus, $\frac{2}{7}$ tank of gas used for each complete trip to Ottawa.

5 0

3 years ago

If a + b = -5 and x + y = -5, what is 6y + 6x - b - a

Novay_Z [31]

6(x +y) -(a +b) = 6(-5) -(-5)
= -25

5 0

3 years ago

Write an equation of a line going through (5,7) and (4 , -4)

Ostrovityanka [42]

Answer:

The equation of this line would be y = 11x - 48

Step-by-step explanation:

To get this equation, we first have to find the slope. We do that with the slope eqaution.

m(slope) = (y2 - y1)/(x2 - x1)

m = (-4 - 7)/(4 - 5)

m = -11/-1

m = 11

Now we can use this slope and either point in point-slope form to find the equation.

y - y1 = m(x - x1)

y - 7 = 11(x - 5)

y - 7 = 11x - 55

y = 11x - 48

6 0

3 years ago