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3 years ago

Find the center, vertices, and foci of the ellipse with equation x squared divided by 81 plus y squared divided by 225 equals 1.

Mathematics

2 answers:

Aliun [14]3 years ago

6 0

To do this the equation must be put into standard form first.

Talja [164]3 years ago

5 0

Answer:

^2 / 81 + y^2 / 225 = 1

Step-by-step explanation:

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“encontrar la integral indefinida y verificar el resultado mediante derivación”

Oliga [24]

$I=\displaystyle\int\frac x{(1-x^2)^3}\,\mathrm dx$

Haz la sustitución:

$y=1-x^2\implies\mathrm dy=-2x\,\mathrm dx$

$\implies I=\displaystyle-\frac12\int\frac{\mathrm dy}{y^3}=\frac1{4y^2}+C=\frac1{4(1-x^2)^2}+C$

Para confirmar el resultado:

$\dfrac{\mathrm dI}{\mathrm dx}=\dfrac14\left(-\dfrac{2(-2x)}{(1-x^2)^3}\right)=\dfrac x{(1-x^2)^3}$

$I=\displaystyle\int\frac{x^2}{(1+x^3)^2}\,\mathrm dx$

Sustituye:

$y=1+x^3\implies\mathrm dy=3x^2\,\mathrm dx$

$\implies I=\displaystyle\frac13\int\frac{\mathrm dy}{y^2}=-\frac1{3y}+C=-\frac1{3(1+x^3)}+C$

(Te dejaré confirmar por ti mismo.)

$I=\displaystyle\int\frac x{\sqrt{1-x^2}}\,\mathrm dx$

Sustituye:

$y=1-x^2\implies\mathrm dy=-2x\,\mathrm dx$

$\implies I=\displaystyle-\frac12\int\frac{\mathrm dy}{\sqrt y}=-\frac12(2\sqrt y)+C=-\sqrt{1-x^2}+C$

$I=\displaystyle\int\left(1+\frac1t\right)^3\frac{\mathrm dt}{t^2}$

Sustituye:

$u=1+\dfrac1t\implies\mathrm du=-\dfrac{\mathrm dt}{t^2}$

$\implies I=-\displaystyle\int u^3\,\mathrm du=-\frac{u^4}4+C=-\frac{\left(1+\frac1t\right)^4}4+C$

Podemos hacer que esto se vea un poco mejor:

$\left(1+\dfrac1t\right)^4=\left(\dfrac{t+1}t\right)^4=\dfrac{(t+1)^4}{t^4}$

$\implies I=-\dfrac{(t+1)^4}{4t^4}+C$

4 0

3 years ago

A population grows with an annual growth rate of 16.5 % per year. (a) what is the monthly growth rate

Shtirlitz [24]

The monthly growth rate would be 16.5% divided by 12 which is 1.3%

8 0

3 years ago

The sum of two numbers is twenty-four. The difference of the two numbers is four.

RSB [31]

Answer:

$x + y = 24$

$x - y = 4$

Now, add these two equations.

You get,

$2x = 28$

$x = \frac{28}{2}$

$x = 14$

Given,

$x + y = 24$

$14 + y = 24$

$y = 24 - 14$

$y = 10$

You can test this to the other equation as well.

$x - y = 4$

$14 - 10 = 4$

Hence, the two numbers are 14 and 10.

3 0

3 years ago

You order office supplies for your company every quarter. The invoices for the first three quarters are $615, $791, and $803. Wh

guapka [62]

Answer:

$2209

Step-by-step explanation:

Add all three numbers together

4 0

3 years ago

Read 2 more answers

There are two non congruent triangles where B=55 degrees a=15 and b=13. Find the measures of the angles of the triangle with the

liq [111]

Answer:

The side c needs to be 12.85 for the triangle to have greatest perimeter

Step-by-step explanation:

We are given;

b = 13

a = 15

Angle at b: B = 55°

Let's find side c.

Using the law of cosines,we have;

b² = a² + c² - 2ac•cos(B)

13² = 15² + c² - 2•15•c•cos(55)

169 = 225 + c² - 30c•cos(55)

c² - 30c•cos(55) + 225 - 169 = 0

c² - 30c•cos(55) + 56 = 0

c² - 30c•(0.5736) + 56 = 0

c² - 17.208c + 56 = 0

Using quadratic formula;

c = [-(-17.208) ± √((-17.208)² - (4•1•56)]/2(1)

c = [17.208 ± √(296.115 - 224)]/2

c = 8.604 ± 4.246

To have the greater perimeter, we need the larger value of c, thus we will use the positive sign and ignore the negative one ;

Thus,

c = 8.604 + 4.246 = 12.85

5 0

3 years ago