Answer:B or C
Step-by-step explanation:
I did the test
I- huh I don’t understand the question
Answer/Step-by-step explanation:
Given:
m<EFH = (5x + 1)°
m<HFG = 62°
m<EFG = (18x + 11)°
Required:
1. Value of x
2. m<EFH
3. m<EFG
SOLUTION:
1. Value of x
m<EFH + m<HFG = m<EFG (angle addition postulate)
(5x + 1) + 62 = (18x + 11)
Solve for x using this equation
5x + 1 + 62 = 18x + 11
5x + 63 = 18x + 11
Subtract 18x from both sides
5x + 63 - 18x = 18x + 11 - 18x
-13x + 63 = 11
Subtract 63 from both sides
-13x + 63 - 63 = 11 - 63
-13x = -52
Divide both sides by -13
-13x/-13 = -52/-13
x = 4
2. m<EFH = 5x + 1
Plug in the value of x
m<EFH = 5(4) + 1 = 20 + 1 = 21°
3. m<EFG = 18x + 11
m<EFG = 18(4) + 11 = 72 + 11 = 83°
Answer:
The surface area is 
Step-by-step explanation:
<u>Step 1: Determine the area of the bottom</u>



<u>Step 2: Determine the area of the triangles</u>




There are two of these right triangles on every side which means that we have 8 of these triangles so we multiply the area that we got by 8.


<u>Step 3: Combine the area to get the surface area</u>


Answer: The surface area is 
Answer:
A. (x - 5)(x - 5)
Step-by-step explanation:
We will do this the old fashioned way...just plain old factoring.
This polynomial is of the form

The product of a and c have to add up to equal the "middle" term, -10.
a = 1, b = -10, c = 25
a * c = 1 * 25 = 25
Now we need the factors of 25 to find the combination of factors that will result in a -10. The factors of 25 are: 1, 25 and 5, 5
5 and 5 add up to be 10, but since we need a -10, we will use -5 and -5. The product of -5 * -5 = 25, so we are not messing anything up by using the negative 5.
Putting them in order in standard form we have

Factor by grouping:

There is an x common to both terms in the first set of parenthesis, so we will factor that out; there is a 5 common to both terms in the second set of parenthesis, so we will factor that out:
x(x - 5) - 5(x - 5)
NOW what's common in both terms is the (x - 5) so we factor THAT out, and what's left gets grouped together:
(x - 5)(x - 5)