$\sqrt{3}x^2+10x+7\sqrt{3}=0\\\\\sqrt3(x^2+\dfrac{10x}{\sqrt{3}}+7)=0\\\\x^2+\dfrac{10x}{\sqrt{3}}+7=0\\\\x^2+\dfrac{10x}{\sqrt{3}}+\dfrac{25}{3}-\dfrac{25}{3} +7=0\\\\(x+\dfrac{5}{\sqrt{3}})^2 = \dfrac{4}{3}\\\\|x+\dfrac{5}{\sqrt{3}}| = \dfrac{2}{\sqrt{3}}\\\\x_1 = \dfrac{2}{\sqrt{3}}-\dfrac{5}{\sqrt{3}} = -\dfrac{3}{\sqrt{3}} = -\sqrt{3}\\\\x_2 = -\dfrac{2}{\sqrt{3}}-\dfrac{5}{\sqrt{3}} = \dfrac{-7}{\sqrt{3}} = -\dfrac{-7\sqrt{3}}{3}$

5 0

3 years ago

4. Ian and his friends are renting a cabin

lesantik [10]

I’m so sorry for this 4 night graph 1.89

4 0

2 years ago

Graph y−5=−23(x+9) using the point and slope given in the equation.

Mashcka [7]

Answer:

Plot (-9,5) then you do rise over run and go down 2 and to the right 3

Step-by-step explanation:

So your points would be (-9,5) and(-6,3)

6 0

3 years ago