3 years ago

Find the inner product for (-8,2) (4.5,18) and state whether the vectors are perpendicular.

Mathematics

1 answer:

Anna71 [15]3 years ago

3 0

Answer: 0; Yes

Step-by-step explanation:

-8 x 4.5 = -36

2 x 18 = 36

-36 + 36 = 0

since the product is zero, the vectors are perpendicular

You might be interested in

Factor as the product of two binomials.<br> 22 + 11x + 18

Dahasolnce [82]

Answer:

11x +40

Step-by-step explanation:

Add 22 and 18 and the result will be as above.

4 0

3 years ago

Jade bought an airplane ticket to New York for $600. Her brother bought a ticket later that same week for $618. The price increa

STALIN [3.7K]

Answer:

the answer to the question is 3%

3 0

2 years ago

What fraction is bigger 1/4 or 16 1/3

Evgen [1.6K]

16 1/3 is bigger than 1/4

5 0

3 years ago

In simplest form, what fraction of the figure is shaded?

yan [13]

5/6, 1/3 hope this helps :))

4 0

3 years ago

Find the exact trigonometric ratios for the angle x whose radian measure is given. (if an answer is undefined, enter undefined.)

Inga [223]

Given the angle $\frac{3\pi}{4}$

angle $\frac{3\pi}{4}$ is equivalent to angle 135 degrees and angle 135 degrees is equvalent to angle 45 degrees in the second quadrant, thus sine is positive but cosine and tangent are negative.

$\sin \frac{3\pi}{4} =\sin \frac{\pi}{4} = \frac{1}{ \sqrt{2} } \\ \\ \csc\frac{3\pi}{4}= \frac{1}{\sin\frac{3\pi}{4}} = \frac{1}{\frac{1}{ \sqrt{2} }} = \sqrt{2} \\ \\ \cos\frac{3\pi}{4} =-\cos \frac{\pi}{4} = -\frac{1}{ \sqrt{2} } \\ \\ \sec\frac{3\pi}{4}= \frac{1}{\cos\frac{3\pi}{4}} = \frac{1}{-\frac{1}{ \sqrt{2} }} =- \sqrt{2} \\ \\ \tan\frac{3\pi}{4} =-\tan \frac{\pi}{4} = -1 \\ \\ \cot\frac{3\pi}{4}= \frac{1}{\tan\frac{3\pi}{4}} = \frac{1}{-1} =- 1$

8 0

3 years ago