for the volume do the equation length×width×height. so 10×4×2.75
To solve this we are going to use the future value of annuity due formula:
![FV=(1+ \frac{r}{n} )*P[ \frac{(1+ \frac{r}{n})^{kt}-1 }{ \frac{r}{n} } ]](https://tex.z-dn.net/?f=FV%3D%281%2B%20%5Cfrac%7Br%7D%7Bn%7D%20%29%2AP%5B%20%5Cfrac%7B%281%2B%20%5Cfrac%7Br%7D%7Bn%7D%29%5E%7Bkt%7D-1%20%7D%7B%20%5Cfrac%7Br%7D%7Bn%7D%20%7D%20%5D)
where

is the future value

is the periodic deposit

is the interest rate in decimal form

is the number of times the interest is compounded per year

is the number of deposits per year
We know for our problem that

and

. To convert the interest rate to decimal form, we are going to divide the rate by 100%:

. Since Ruben makes the deposits every 6 months,

. The interest is compounded semiannually, so 2 times per year; therefore,

.
Lets replace the values in our formula:
![FV=(1+ \frac{r}{n} )*P[ \frac{(1+ \frac{r}{n})^{kt}-1 }{ \frac{r}{n} } ]](https://tex.z-dn.net/?f=FV%3D%281%2B%20%5Cfrac%7Br%7D%7Bn%7D%20%29%2AP%5B%20%5Cfrac%7B%281%2B%20%5Cfrac%7Br%7D%7Bn%7D%29%5E%7Bkt%7D-1%20%7D%7B%20%5Cfrac%7Br%7D%7Bn%7D%20%7D%20%5D)
![FV=(1+ \frac{0.1}{2} )*420[ \frac{(1+ \frac{0.1}{2})^{(2)(15)}-1 }{ \frac{01}{2} } ]](https://tex.z-dn.net/?f=FV%3D%281%2B%20%5Cfrac%7B0.1%7D%7B2%7D%20%29%2A420%5B%20%5Cfrac%7B%281%2B%20%5Cfrac%7B0.1%7D%7B2%7D%29%5E%7B%282%29%2815%29%7D-1%20%7D%7B%20%5Cfrac%7B01%7D%7B2%7D%20%7D%20%5D)
We can conclude that the correct answer is <span>
$29,299.53</span>
The answer is A because there are only acute angles
Answer:
Let s be the number of shorts and t be the number of T-shirts. s shorts cost $12s and t T-shirts cost $5t, then you have to find min and max value for the function f(s,t)=12s+5t.
The shaded domain (see image) is defined from the system of unequalities. The green lines are the graphs of function f(x,y) and it intersects domain in first point (0,5) (the minimum point) and in last point (20,0) (the maximum point). So,
.
Step-by-step explanation:
Answer:
A
Step-by-step explanation:
Put brackets around the first two tems.
y = (x^2 - 8x) + 29
Take 1/2 coefficient of the linear term -8. Square that result. Add it inside the brackets.
1/2 (- 8) = - 4
(- 4)^2 = 16
y = (x^2 - 8x + 16) + 29
Subtract 16 outside the brackets.
y = (x^2 - 8x + 16) + 29 - 16
Do the subtraction
y = (x^2 - 8x + 16) + 13
Represent what is inside the brackets as a square.
y = ( x - 4)^2 + 13
The answer is A