Formula works when n=1
Assume the formula also works, when n=k.
Prove that the formula works, when n=k+1
Since the formula has been proven with n=1 and n=k+1, it is true.
Let x be the number, then 60 = 40% of x & x =60/40%=60/0.4=150
then the number of which 60 represent 40% of it is 150
2) Let x be the time needed to the 16 clerks to finish the job
In one day the 32 clerks complete a portion of 32/22 of the job
In one day the 16 clerks complete a portion of 16/x of the job
So in 1 day===> 32/22 =16/x ==> x=(22*16)/32 = 11 days
Answer:
z = -3
Step-by-step explanation:
Simplifying
3z + -3 = 2z + -6
Reorder the terms:
-3 + 3z = 2z + -6
Reorder the terms:
-3 + 3z = -6 + 2z
Solving
-3 + 3z = -6 + 2z
Solving for variable 'z'.
Move all terms containing z to the left, all other terms to the right.
Add '-2z' to each side of the equation.
-3 + 3z + -2z = -6 + 2z + -2z
Combine like terms: 3z + -2z = 1z
-3 + 1z = -6 + 2z + -2z
Combine like terms: 2z + -2z = 0
-3 + 1z = -6 + 0
-3 + 1z = -6
Add '3' to each side of the equation.
-3 + 3 + 1z = -6 + 3
Combine like terms: -3 + 3 = 0
0 + 1z = -6 + 3
1z = -6 + 3
Combine like terms: -6 + 3 = -3
1z = -3
Divide each side by '1'.
z = -3
Simplifying
z = -3
So since you haven't given us the actaul equation Im gonna guess that x equals to -7, and lets just say the x equals to uhhhhhh, i dont know how about 42? That sound about right? What im trying to say is next time can you please give out the equation? If you respond I could probably help you next time.
Y=x^2-4x+8 and 4x+y=12 so y=12-4x, insert y in the quadratic to get
12-4x=x^2-4x+8
12=x^2+8
0=x^2-4=(x-2)(x+2)
So the solutions are x=2 and x=-2.