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tigry1 [53]
3 years ago
15

What are the solutions to the following system of equations? Select the correct answer. y=x^2-4x+8 4x+y=12

Mathematics
2 answers:
Murrr4er [49]3 years ago
8 0
Reduce the second equation to y= -4x + 12, then subtract the two equations. (Quadratic on top), to get y=x^2 -4. Then, plug in an x,y coordinate if you have one.
lorasvet [3.4K]3 years ago
7 0
Y=x^2-4x+8 and 4x+y=12 so y=12-4x, insert y in the quadratic to get
12-4x=x^2-4x+8
12=x^2+8
0=x^2-4=(x-2)(x+2)
So the solutions are x=2 and x=-2.
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Answer:

  $10,000

Step-by-step explanation:

Let x represent the amount invested in the 5.5% bond.

For an annual income of $1800, we want ...

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One factor of One factor of f(x)=5x^3+5x^2-170x + 280 is (x +
SpyIntel [72]

Answer:

x = –7, x = 2, or x = 4 are factors of f(x).

Step-by-step explanation:

Given : f(x)  = 5x³ +5x²-170x +280 and x + 7 is one factor .

To find  : What are all the roots of the function.

Solution :  f(x)  = 5x³ +5x²-170x +280 .

We have given that x + 7 is factor that mean x = -7 is factor of f(x )

When we divide f(x) by x +7 we get

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Taking common 5 from equation

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On dividing by 5 both sides

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On factoring

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Taking common x from first two terms and -4 from last two terms

x ( x -2) -4 (x -2) = 0

On grouping

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x -2 =0

x =2

x-4 =0

x = 4

Therefore, x = –7, x = 2, or x = 4 are factors of f(x).

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