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tigry1 [53]
3 years ago
15

What are the solutions to the following system of equations? Select the correct answer. y=x^2-4x+8 4x+y=12

Mathematics
2 answers:
Murrr4er [49]3 years ago
8 0
Reduce the second equation to y= -4x + 12, then subtract the two equations. (Quadratic on top), to get y=x^2 -4. Then, plug in an x,y coordinate if you have one.
lorasvet [3.4K]3 years ago
7 0
Y=x^2-4x+8 and 4x+y=12 so y=12-4x, insert y in the quadratic to get
12-4x=x^2-4x+8
12=x^2+8
0=x^2-4=(x-2)(x+2)
So the solutions are x=2 and x=-2.
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Part 1: getting the area of the entrance
The entrance has a trapezoid shape.
Area of trapezoid can be calculated using the following rule:
Area of trapezoid = average base * height
The aveage base = (b1+b2)/2 = (8+16)/2 = 12 ft
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Part 2: getting the area of the house:
area of house = area of back porch + area of side deck + area of play room + area of entrance
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The back porch is a square with side length = 6 ft
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ii- getting the area of side deck:
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iii- getting the area of play room:
The play room is a rectangle whose length is 14 ft and width is 16 ft
Therefore:
area of play room = 14*16 = 224 ft^2
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