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gizmo_the_mogwai [7]
2 years ago
6

What is the area of this figure? Enter your answer in the box.

Mathematics
2 answers:
alisha [4.7K]2 years ago
7 0
The answer is 28 I think
Alex787 [66]2 years ago
6 0

Answer:

400 sq. in.

Step-by-step explanation:

the parallelogram in the figure has an area of 320 sq. in.

and the right triangle at the top right has an area of 80 sq. in.

adding both areas would equal to 400 sq. in.

( if you're wondering,what about the right triangle at the bottom left?Well that triangle actually gives us the height of the parallelogram which is 16.therefore the triangle's area is already found in the area of the parallelogram.As you should know the area to a parallelogram is A=bh ,and the base is 20 so multiplying 16 x 20 that equals 320.Therefore the triangle's area is already found in the area of the parallelogram.)

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3 0
3 years ago
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Can someone please help me ASAP​
Sonja [21]

Answer:

x^2 + 5n = 4mx

=> x^2 - 4mx + 5n = 0

D=0 (since one root then roots are equal)

b^2-4ac = 0

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7 0
3 years ago
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Orlov [11]
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2 years ago
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8 0
2 years ago
Which is the approximate solution for the system of equations 3x+4y=2 and 4x+y=-4
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3x+4y=2\qquad\text{subtract 3x from both sides}\\\\4y=-3x+2\qquad\text{divide both sides by 4}\\\\y=-\dfrac{3}{4}x+\dfrac{2}{4}\to y=-\dfrac{3}{4}x+\dfrac{1}{2}\\\\for\ x=0\to y=-\dfrac{3}{4}(0)+\dfrac{1}{2}=0+\dfrac{1}{2}=\dfrac{1}{2}\to\left(0,\ \dfrac{1}{2}\right)\\\\for\ x=2\to y=-\dfrac{3}{4}(2)+\dfrac{1}{2}=-\dfrac{3}{2}+\dfrac{1}{2}=-\dfrac{2}{2}=-1\to(2,\ -1)\\--------------------------------\\

4x+y=-4\qquad\text{subtract 4x from both sides}\\\\y=-4x-4\\\\for\ x=0\to y=-4(0)-4=0-4=-4\to(0,\ -4)\\\\for\ x=-1\to y=-4(-1)-4=4-4=0\to(-1,\ 0)\\\\Answer:\ \boxed{A.\ (-1.4,\ 1.5)}

6 0
3 years ago
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