Answer: If 7+5i is a zero of a polynomial function of degree 5 with coefficients, then so is <u>its conjugate 7-i5</u>.
Step-by-step explanation:
- We know that when a complex number
is a root of a polynomial with degree 'n' , then the conjugate of the complex number (
) is also a root of the same polynomial.
Given: 7+5i is a zero of a polynomial function of degree 5 with coefficients
Here, 7+5i is a complex number.
So, it conjugate (
) is also a zero of a polynomial function.
Hence, if 7+5i is a zero of a polynomial function of degree 5 with coefficients, then so is <u>its conjugate 7-i5</u>.
Answer:
The answer to the mean is 66.4
Step-by-step explanation:
58+63+68+72+71
Answer:
x=60
Step-by-step explanation:
61+59=120
180-120=60
⇒ 
⇒ 
⇒
; sin(x) ≠ 0, cos(x) ≠ 0
⇒ 
; sin(x) ≠ 0, cos(x) ≠ 0
⇒ 
Use the Unit Circle to determine when
Answer: 45° and 315° 
Answer:
D. y = 3/5x + 13/5
Step-by-step explanation:
The slope of the desired line is the ratio of the difference in y-values to the difference in x-values:
m = Δy/Δx = (2 -5)/(-1 -4) = -3/-5 = 3/5 . . . . . . eliminates choices B and C
The slope-intercept equation will then be ...
y = mx + b . . . . . . . generic slope-intercept form
y = 3/5x + b . . . . . . put in m; true for some b that puts the given points on the line
Using the first point, we have ...
5 = 3/5×4 + b
25/5 = 12/5 + b
13/5 = b . . . . . . . . . subtract 12/5
Then the equation is ...
y = 3/5x + 13/5
_____
You know as soon as you consider putting a point value in the equation ...
y = 3/5x + b
that the equation of choice A cannot work. That only leaves choice D.
