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3 years ago

Need help with this question

Mathematics

2 answers:

Snezhnost [94]3 years ago

8 0

Answer:20

2+2=4

8+2=10

10x4x1/2

40x1/2

=20

Yanka [14]3 years ago

6 0

Answer:

Step-by-step explanation:

The area of a kite is equal to the product of both of its diagonals and 1/2.

First diagonal:

2 + 2 = 4

Second diagonal:

8 + 2 = 10

Find the area.

10 × 4 × 1/2

40 × 1/2

= 20

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Step-by-step explanation:

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2 years ago

Solve the equation for x, and enter your answer below. 7 x -5= 65

Sedaia [141]

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Step-by-step explanation:

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3 0

3 years ago

Read 2 more answers

The height H of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 9

mariarad [96]

Answer:

The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.

Step-by-step explanation:

Statement is incorrect. Correct form is presented below:

The height $h(t)$ of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 90 feet per second is given by equation $h(t) = 3 +90\cdot t -16\cdot t^{2}$ , where $t$ is time in seconds. After how many seconds will the ball be 84 feet above the ground.

We equalize the kinematic formula to 84 feet and solve the resulting second-order polynomial by Quadratic Formula to determine the instants associated with such height:

$3+90\cdot t -16\cdot t^{2} = 84$

$16\cdot t^{2}-90\cdot t +81 = 0$ (1)

By Quadratic Formula:

$t_{1,2} = \frac{90\pm \sqrt{(-90)^{2}-4\cdot (16)\cdot (81)}}{2\cdot (16)}$

$t_{1} = 4.5\,s$ , $t_{2} = 1.125\,s$

The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.

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2 years ago