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3 years ago

Find the area of the following trapezoid

Mathematics

2 answers:

Orlov [11]3 years ago

8 0

Answer:

82 cm is the area of trapezoid

erik [133]3 years ago

4 0

Answer:

Step-by-step explanation:

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mafiozo [28]

Answer:

the answer is 14,880 and its bigger :D 14880>12400

Step-by-step explanation:

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3 years ago

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Vesnalui [34]

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3 years ago

Tina’s pay stub is shown at right. Find the missing numbers.

kolbaska11 [484]

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5 0

3 years ago

Please help me on this!!<br> 5n+17≥n–3≥–15+5n

DENIUS [597]

Answer:

-5 ≤ n ≤ 3

Step-by-step explanation:

Firstly we solve the equation two at a time;

5n + 17 ≥ n - 3

5n - n ≥ -3 - 17

4n ≥ -20

n ≥ -5

-5 ≤ n

n - 3 ≥ -15 + 5n

n - 5n ≥ -15 + 3

-4n ≥ -12

-n ≥ -3

n ≤ 3

Therefore,

5n+17 ≥ n–3 ≥ –15+5n, becomes

-5 ≤ n ≤ 3

6 0

3 years ago

According to a 2018 survey by Bankrate, 20% of adults in the United States save nothing for retirement (CNBC website). Suppose t

nalin [4]

Answer:

0.5981 = 59.81% probability that three or less of the selected adults have saved nothing for retirement

Step-by-step explanation:

For each adult, there are only two possible outcomes. Either they save nothing for retirement, or they save something. The probability of an adult saving nothing for retirement is independent of any other adult. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

20% of adults in the United States save nothing for retirement (CNBC website).

This means that $p = 0.2$

Suppose that sixteen adults in the United States are selected randomly.

This means that $n = 16$

What is the probability that three or less of the selected adults have saved nothing for retirement?

This is:

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{16,0}.(0.2)^{0}.(0.8)^{16} = 0.0281$

$P(X = 1) = C_{16,1}.(0.2)^{1}.(0.8)^{15} = 0.1126$

$P(X = 2) = C_{16,2}.(0.2)^{2}.(0.8)^{14} = 0.2111$

$P(X = 3) = C_{16,3}.(0.2)^{3}.(0.8)^{13} = 0.2463$

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0281 + 0.1126 + 0.2111 + 0.2463 = 0.5981$

0.5981 = 59.81% probability that three or less of the selected adults have saved nothing for retirement

4 0

3 years ago