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murzikaleks [220]
4 years ago
10

on the day their child was born, her parents deposited $15,000 in a savings account that earns 10% interest annually. how much i

s in the account the day the child turns 16 years old (rounded to the nearest cent)?
Mathematics
2 answers:
Inga [223]4 years ago
6 0
15,000 * (1.1)^16

I don't have a calculator on me to do it but that's the working.
Vedmedyk [2.9K]4 years ago
4 0
15 because theirs 15 characters in my name
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What is the vertex of the graph of f(x) = 5x + 3] + 7?
pickupchik [31]
F(x)=5x+10
5x=-10
x=-10/5
x=-2


Result is f(-2).
4 0
3 years ago
solve for b 1/4(b-8)=2. I hope you have time to answer this. Thank you so much for your time you guys make me so happy
Mademuasel [1]

Answer:

16

Step-by-step explanation:

1/4(b-8)=2

b-8=2/(1/4)

b-8=2(4/1)

b-8=8

b=8+8

b=16

8 0
3 years ago
Read 2 more answers
Aidan drops a rock from a cliff after 4.0s, the rock is moving at 39.2m/s what is the acceleration of the rock
Cerrena [4.2K]

Here,

time=4.0s

velocity=39.2m/s

Formula:

a=v/t

=39.2/4.0

=9.8 (ms-2)

3 0
3 years ago
V=u+at<br> u= 2<br> a= -5<br> t=1/2 <br> what is the value of v
artcher [175]
At= -5(1/2)
at= -2.5
v= u + at
v= 2 + (-2.5)
v= -0.5
3 0
3 years ago
Read 2 more answers
Help me Please....................
MakcuM [25]

9514 1404 393

Answer:

  1.3363

Step-by-step explanation:

The basic idea here is to find an expression for the direction vector between a point on L1 and a point on L2. Then, solve for the points on L1 and L2 that make that vector perpendicular to both lines L1 and L2. (The dot product of direction vectors is zero.) The distance between the points found is the shortest distance between the lines.

__

Let P be a point on L1. Then the parametric equation for P is ...

  P = (6t, 0, -t) . . . . . . origin + t × direction vector

Let Q be a point on L2. The direction vector for L2 is given by the difference between the given points. It is (4-1, 1-(-1), 6-1) = (3, 2, 5). Then the parametric equation for Q is ...

  Q = (3s+1, 2s-1, 5s+1) . . . . (1, -1, 1) + s × direction vector

The direction vector for PQ is ...

  Q -P = (3s+1-6t, 2s-1, 5s+1+t)

The dot product of this and the two lines' direction vectors will be zero:

  (3s+1-6t, 2s-1, 5s+1+t)·(6, 0, -1) = 0 = 13s -37t +5 . . . perpendicular to L1

  (3s+1-6t, 2s-1, 5s+1+t)·(3, 2, 5) = 0 = 38s -13t +6 . . . perpendicular to L2

The solution to these equations is ...

  s = -157/1237

  t = 112/1237

Then (Q-P) becomes (94, -1551, 564)/1237, and its length is ...

  |PQ| = √(94² +1551² +564²)/1237 ≈ 1.3363

The distance between the two lines is about 1.3363 units.

8 0
3 years ago
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