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nexus9112 [7]
3 years ago
11

For friends are sharing a meal. They each agreed to pay 25% of the total cost. The meal costs $115. How much does each friend pa

y?
A:$26.15. C:$32.12

B:$28.75. D:$35.65
Mathematics
2 answers:
Tatiana [17]3 years ago
8 0

Each  \: friend  \: pays: \frac{25 \times 115}{100}  =  \frac{115}{4}  = 28.75 \\ \Rightarrow B.\:\$28.75

Juli2301 [7.4K]3 years ago
5 0

There are two ways to do this:

Way 1- Since you know there are 4 people and each will pay 25%, you know that every person will pay equally / the same amount so you can just do 115/4 and get $28.75 per person

Way 2- You can convert 25% into a decimal by multiplying it by 100 and getting 0.25 and multiplying 0.25 x 115 to get 25% of 115, which is what everyone will pay and you get B $28.75

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Answer:

a

  The 95% confidence interval is  0.0503  <   p < 0.1297

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The sample proportion is  \r p =  0.09

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The critical value is  Z_{\frac{\alpha }{2} } =  1.96

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 The standard error is  SE   =0.020

Step-by-step explanation:

From the question we are told that

   The  sample size is  n =  200

     The number of defective is  k =  18

The null hypothesis is  H_o  :  p  =  0.08

The  alternative hypothesis is  H_a  :  p > 0.08

Generally the sample proportion is mathematically evaluated as

            \r p =  \frac{18}{200}

            \r p =  0.09

Given that the confidence level is  95% then the level  of significance is mathematically evaluated as

        \alpha  =  100 -  95

        \alpha  =  5\%

        \alpha  =  0.05

Next we obtain the critical value of  \frac{ \alpha }{2} from the normal distribution table, the value is  

        Z_{\frac{\alpha }{2} } =  1.96

Generally the standard of error is mathematically represented as

          SE   =  \sqrt{\frac{\r p (1 -  \r p)}{n} }

substituting values

         SE   =  \sqrt{\frac{0.09  (1 -  0.09)}{200} }

        SE   =0.020

The  margin of error is  

       E =  Z_{\frac{ \alpha }{2} }  * SE

=>    E =  1.96  *  0.020

=>   E =  0.0397

The  95% confidence interval is mathematically represented as

     \r p  -  E  <  \mu <  p <  \r p  + E

=>   0.09 - 0.0397  <  \mu <  p < 0.09 + 0.0397

=>  0.0503  <   p < 0.1297

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3 years ago
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