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makvit [3.9K]
3 years ago
10

Solve this quadratic equation. 6x2 - 2x = 7

Mathematics
1 answer:
rjkz [21]3 years ago
5 0

Answer:

x₁ = (1 + √43)/6

x₂ = (1 - √43)/6

Step-by-step explanation:

6x² - 2x = 7

6x² - 2x - 7 = 0

Formula

ax² + bx + c = 0

a = 6 ; b = - 2 ; c = - 7

x₁/₂ = [-b ± √(b²- 4ac)]/2a

x₁/₂ = (2 ± √4 + 4×6×-7)/12

x₁/₂ = (2 ± √172)/12

x₁/₂ = (2 ± 2√43)/12

x₁/₂ = 2(1 ± √43)/12

x₁/₂ = (1 ± √43)/6

x₁ = (1 + √43)/6

x₂ = (1 - √43)/6

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Scores on a test are normally distributed with a mean of 81.2 and a standard deviation of 3.6. What is the probability of a rand
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<u>Answer:</u>

The probability of a randomly selected student scoring in between 77.6 and 88.4 is 0.8185.

<u>Solution:</u>

Given, Scores on a test are normally distributed with a mean of 81.2  

And a standard deviation of 3.6.  

We have to find What is the probability of a randomly selected student scoring between 77.6 and 88.4?

For that we are going to subtract probability of getting more than 88.4 from probability of getting more than 77.6  

Now probability of getting more than 88.4 = 1 - area of z – score of 88.4

\mathrm{Now}, \mathrm{z}-\mathrm{score}=\frac{88.4-\mathrm{mean}}{\text {standard deviation}}=\frac{88.4-81.2}{3.6}=\frac{7.2}{3.6}=2

So, probability of getting more than 88.4 = 1 – area of z- score(2)

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= 0.0228.

Now probability of getting more than 77.6 = 1 - area of z – score of 77.6

\mathrm{Now}, \mathrm{z}-\text { score }=\frac{77.6-\text { mean }}{\text { standard deviation }}=\frac{77.6-81.2}{3.6}=\frac{-3.6}{3.6}=-1

So, probability of getting more than 77.6 = 1 – area of z- score(-1)

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= 0.8413

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Hence, the probability of a randomly selected student getting in between 77.6 and 88.4 is 0.8185.

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