Solve this quadratic equation. 6x2 - 2x = 7

Mathematics

1 answer:

rjkz [21]3 years ago

5 0

Answer:

x₁ = (1 + √43)/6

x₂ = (1 - √43)/6

Step-by-step explanation:

6x² - 2x = 7

6x² - 2x - 7 = 0

Formula

ax² + bx + c = 0

a = 6 ; b = - 2 ; c = - 7

x₁/₂ = [-b ± √(b²- 4ac)]/2a

x₁/₂ = (2 ± √4 + 4×6×-7)/12

x₁/₂ = (2 ± √172)/12

x₁/₂ = (2 ± 2√43)/12

x₁/₂ = 2(1 ± √43)/12

x₁/₂ = (1 ± √43)/6

x₁ = (1 + √43)/6

x₂ = (1 - √43)/6

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Use Euclid's division algorithm to find the HCF of 441, 567, 693

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Let a = 693, b = 567 and c = 441

Now first we will find HCF of 693 and 567 by using Euclid’s division algorithm as under

693 = 567 x 1 + 126
567 = 126 x 4 + 63
126 = 63 x 2 + 0
Hence, HCF of 693 and 567 is 63

Now we will find HCF of third number i.e., 441 with 63 So by Euclid’s division alogorithm for 441 and 63

441 = 63 x 7+0
=> HCF of 441 and 63 is 63.

Hence, HCF of 441, 567 and 693 is 63.

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