There are

ways of selecting two of the six blocks at random. The probability that one of them contains an error is

So

has probability mass function

These are the only two cases since there is only one error known to exist in the code; any two blocks of code chosen at random must either contain the error or not.
The expected value of finding an error is then
1 3 6 concrete ratio
Concrete
Proportions by Cement No. of 50 kg Sand to total aggregate
1:3:6 4.0 31
1:4:5 4.0 41
1:3:5 4.4 35
1:4:4 4.5 47
Answer:
c = a - 16
Step-by-step explanation:
Given
a = b + 12 ( subtract 12 from both sides )
a - 12 = b
Substitute b = a - 12 into b = c + 4
a - 12 = c + 4 ( add 12 to both sides )
a = c + 16 ( subtract 16 from both sides )
c = a - 16
Answer:
5x + 8
Step-by-step explanation:
it just is
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