Whats the price of 55% of 56.99

Evaluate the expression \{10 x 7\}+(10 - 6){10×7}+(10−6)left brace, 10, times, 7, right brace, plus, left parenthesis, 10, minus

aliya0001 [1]

What grade is this? I can get the answer of it but I forgot how

3 0

3 years ago

Read 2 more answers

Only male crickets chirp. They chirp at different rates depending on their species and the temperature of their environment. Sup

bezimeni [28]

Answer:

4920

7084800

2585952000

Step-by-step explanation:

82 chirps = 1 minute

We have 60 minutes in one hour, so 82 x 60 =4920 chirps in one hour

In 24 hours we have 60x24 = 1440 minutes and in one minutes we have 4920 chirps,

Therefore 4920 x 1440 mins =7084800 chirps in one day .

There are 365 days in a year and in one day the cricket chirps 7084800, so 365 days x 7084800 = 258595200 chirps in a year

6 0

3 years ago

An employee earns $175 for 15 hours work.<br> Find the constant of variation.

LiRa [457]

Answer:

11.67

Step-by-step explanation:

Given: Employee earn $175 for 15 hours

We know, the constant of variation means the rate of change.

To know The constant of variation, we need to find how much employee earn each hour.

∴ Constant of variation= $\frac{Total\ earning}{Total\ working\ hours}$

Constant of variation= $\frac{175}{15}= 11.666$

∴ Constant of variation= 11.67. (rounding off)

8 0

3 years ago

A square pyramid is sliced in half, parallel to the base.

DIA [1.3K]

Answer:

I think the answer is a because it not getting any smaller

7 0

2 years ago

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A civil engineer is analyzing the compressive strength of concrete. Compressive strength is normally distributed with σ = 31.62

AysviL [449]

Answer:

A sample size of at least 737 specimens is required.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.99}{2} = 0.005$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.005 = 0.995$ , so $z = 2.575$

Now, find the width M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

In this problem, we have that:

$M = 3, \sigma = 31.62$

So:

$M = z*\frac{\sigma}{\sqrt{n}}$

$3 = 2.575*\frac{31.62}{\sqrt{n}}$

$3\sqrt{n} = 81.4215$

$\sqrt{n} = 27.1405$

$n = 736.60$

A sample size of at least 737 specimens is required.

6 0

3 years ago