0.34 + [9.8 - (5.4+ 1.4)<br> 0.3- + [9.8 -<br> Add.

A line through which two points would be parallel to a line with a slope of 1/4?

12345 [234]

Answer:

thats a long question

Step-by-step explanation:

sorry I'm doing a competition for who ever reaches 1k points

7 0

2 years ago

How do i solve x squared = 4x -5

ICE Princess25 [194]

Answer:

x = 2 ±i

Step-by-step explanation:

x^2 = 4x-5

Subtract 4x from each side

x^2 - 4x = 4x-5 -4x

x^2 - 4x= -5

Complete the square

Take the coefficient of the x term, divide by 2 and square it

-4/2 =2 2^2 =4

Add 4 to each side

x^2 -4x+4 = -5 +4

The left side is (x-coefficient of the x term/2)^2

(x-2)^2 = -1

Take the square root of each side

sqrt((x-2)^2) = sqrt(-1)

x-2 = ±i

Add 2 to each side

x-2+2 = 2 ±i

x = 2 ±i

6 0

2 years ago

60% markup of 129.50

Vedmedyk [2.9K]

59.25 is the answer m8

4 0

3 years ago

marta has 7 more than half as many books as lucy. if l is the number of the books lucky has which expression could be use to fin

artcher [175]

Answer:

M= 1/2(x)+7

Step-by-step explanation:

Let M = Martha.

Let X = Number of Lucy's blocks.

Martha has half the amount as Lucy - 1/2(x)

Then 7 more than that - 1/2 (x) + 7

3 0

2 years ago

Read 2 more answers

A bag contain 3 black balls and 2 white balls.

Troyanec [42]

Answer:

Step-by-step explanation:

Total number of balls = 3 + 2 = 5

1)

a)

$Probability \ of \ taking \ 2 \ black \ ball \ with \ replacement\\\\ = \frac{3C_1}{5C_1} \times \frac{3C_1}{5C_1} =\frac{3}{5} \times \frac{3}{5} = \frac{9}{25}\\\\$

b)

$Probability \ of \ one \ black \ and \ one\ white \ with \ replacement \\\\= \frac{3C_1}{5C_1} \times \frac{2C_1}{5C_1} = \frac{3}{5} \times \frac{2}{5} = \frac{6}{25}$

c)

Probability of at least one black( means BB or BW or WB)

$=\frac{3}{5} \times \frac{3}{5} + \frac{3}{5} \times \frac{2}{5} + \frac{2}{5} \times \frac{3}{5} \\\\= \frac{9}{25} + \frac{6}{25} + \frac{6}{25}\\\\= \frac{21}{25}$

d)

Probability of at most one black ( means WW or WB or BW)

$=\frac{2}{5} \times \frac{2}{5} + \frac{3}{5} \times \frac{2}{5} \times \frac{2}{5} + \frac{3}{5}\\\\= \frac{4}{25} + \frac{6}{25} + \frac{6}{25}\\\\=\frac{16}{25}$

2)

a) Probability both black without replacement

$=\frac{3}{5} \times \frac{2}{4}\\\\=\frac{6}{20}\\\\=\frac{3}{10}$

b) Probability of one black and one white

$=\frac{3}{5} \times \frac{2}{4}\\\\=\frac{6}{20}\\\\=\frac{3}{10}$

c) Probability of at least one black ( BB or BW or WB)

$=\frac{3}{5} \times \frac{2}{4} + \frac{3}{5} \times \frac{2}{4} + \frac{2}{5} \times \frac{3}{4}\\\\=\frac{6}{20} + \frac{6}{20} + \frac{6}{20} \\\\=\frac{18}{20} \\\\=\frac{9}{10}$

d) Probability of at most one black ( BW or WW or WB)

$=\frac{3}{5} \times \frac{2}{4} + \frac{2}{5} \times \frac{1}{4} + \frac{2}{5} \times \frac{3}{4}\\\\=\frac{6}{20} + \frac{2}{20} + \frac{6}{20} \\\\=\frac{14}{20}\\\\=\frac{7}{10}$

6 0

2 years ago

0.34 + [9.8 - (5.4+ 1.4) 0.3- + [9.8 - Add.