Answer:
The distance at which the timekeeper is the race car at the start is 50 feet.
Step-by-step explanation:
You know that the car's distance from the timekeeper is represented by
y=293*x +50
where x is time in seconds and y is distance in feet from the timekeeper's position.
You want to determine how far the timekeeper is from the race car at the start. That is, the distance the timekeeper is from the car when the time is equal to zero. This indicates that x = 0. Replacing x by that value in the expression of the distance of the car from the timekeeper as a function of time and solving:
y=293*0 +50
you get:
y=50
<u><em>The distance at which the timekeeper is the race car at the start is 50 feet.</em></u>
If you are trying to find h, then its very simple.
So lets see 5+7=12
So 17-12=5
So lets check to see if h=5
5+5+7
5+5=10+7=17 so h is 5. :)
Answer:
17
Step-by-step explanation:
Variance=(standard deviation)^2
√289=standard deviation
Standard deviation=17
Answer:
see explanation
Step-by-step explanation:
Note there is a common ratio between consecutive terms of the sequence, that is
- 450 ÷ 15 = 13500 ÷ - 450 = - 405000 ÷ 13500 = - 30
Thus to obtain the next term in the sequence multiply the previous term by - 30
start with 15 and multiply by - 30
S= savings before she bought the dress s - $55 would be her new balance after she bought the dress.
We could also talk about her savings now (after her purchase). If we let n=now
n + $55 would be her balance before she bought the dress.
