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JulijaS [17]
3 years ago
11

If a planet is orbiting along path C in the figure below, explain why it stays in orbit. Refer to pic

Physics
2 answers:
Snowcat [4.5K]3 years ago
5 0
 Orbits<span> of </span>planets are typically elliptical, and the central mass being orbited is at a focal point of the ellipse. The planet stays in orbit due to a strong atmosphere and gravity. Also, the planet's inertia would keep it on course. Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.
Wittaler [7]3 years ago
4 0

Answer:

Due to gravitational force between the planet and the sun.

Explanation:

According to Newton's first law of motion, a body remains in the state of motion or rest unless an unbalanced external force acts on it. A planet would move in straight path had there been no force acting on it. It stays in its elliptical orbit around the Sun because of the gravitational force between the sun and the planet. The planet is orbiting along path C in the figure, instead of Path A due to gravitational force.

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How does the structure of the stigma aid in pollination
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3 years ago
A 3.0-kg block starts at rest at the top of a 37° incline, which is 5.0 m long. Its speed when it reaches the bottom is 2.0 m/s.
Mama L [17]

Answer: f_{r} = 16.49N

Explanation: The object is placed on an inclined plane at an angle of 37° thus making it weight have two component,

W_{x} = horizontal component of the weight = mgsinФ

W_{y} = vertical component of weight = mgcosФ

Due to the way the object is positioned, the horizontal component of force will accelerate the object thus acting as an applied force.

by using newton's law of motion, we have that

mgsinФ - f_{r} = ma

where m = mass of object=5kg

a = acceleration= unknown

Ф = angle of inclination = 37°

g = acceleration due to gravity = 9.8m/s^{2}

f_{r} = frictional force = unknown

we need to first get the acceleration before the frictional force which is gotten by using the equation below

v^{2} = u^{2} + 2aS

where v = final velocity = 2m/s

u = initial velocity = 0m/s (because the object started from rest)

a= unknown

S= distance covered = length of plane = 5m

2^{2} = 0^{2} + 2*a*5\\\\4= 10 *a\\\\a = \frac{4}{10} \\a = 0.4m/s^{2}

we slot in a into the equation below to get frictional force

mgsinФ - f_{r} = ma

3 * 9.8 * sin 37 - f_{r} = 3* 0.4

17.9633 - f_{r} =  1.2

f_{r} = 17.9633 - 1.2

f_{r} = 16.49N

4 0
3 years ago
Why does a partially inflated weather balloon expand as it rises?
marusya05 [52]
Air pressure pushing in on the balloon decreases as the balloon rises.
3 0
3 years ago
Read 2 more answers
Question is attatched!
lina2011 [118]
All it does is lets him pull in a more convenient direction to raise the load. It has no effect on the required force.
4 0
3 years ago
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