Answer:
W = 28226.88 N
Explanation:
Given,
Mass of the satellite, m = 5832 Kg
Height of the orbiting satellite from the surface, h = 4.13 x 10⁵ m
The time period of the orbit, T = 1.9 h
= 6840 s
The radius of the planet, R = 4.38 x 10⁶ m
The time period of the satellite is given by the formula
second
Squaring the terms and solving it for 'g'
g = 4 π² 
m/s²
Substituting the values in the above equation
g = 4 π² 
g = 4.84 m/s²
Therefore, the weight
w = m x g newton
= 5832 Kg x 4.84 m/s²
= 28226.88 N
Hence, the weight of the satellite at the surface, W = 28226.88 N
The sun has orbited along time so when they ask theses questions I give you the right answer I think lol
Answer:
answer the question i have asked go to my account
Explanation:
can i get brainliest
Answer:
(A). The order of the bright fringe is 6.
(B). The width of the bright fringe is 3.33 μm.
Explanation:
Given that,
Fringe width d = 0.5 mm
Wavelength = 589 nm
Distance of screen and slit D = 1.5 m
Distance of bright fringe y = 1 cm
(A) We need to calculate the order of the bright fringe
Using formula of wavelength
Put the value into the formula
(B). We need to calculate the width of the bright fringe
Using formula of width of fringe
Put the value in to the formula
Hence, (A). The order of the bright fringe is 6.
(B). The width of the bright fringe is 3.33 μm.
