All categories

3 years ago

Why do the star constellations seem to move across the sky

Physics

2 answers:

cricket20 [7]3 years ago

7 0

Answer:

because the world moves around and around rotating in a circle and circling around the sun so as we move the stars stay the same but to our view it looks like their moving but in reality we are.

Explanation:

barxatty [35]3 years ago

5 0

Answer: These apparent star tracks are in fact not due to the stars moving, but to the rotational motion of the Earth. As the Earth rotates with an axis that is pointed in the direction of the North Star, stars appear to move from east to west in the sky.

Explanation: why do the star constellations seem to move across the sky

You might be interested in

Ariel's puppy weighs 15 lb. Heather's puppy weighs 50 N. Whose puppy weighs more?

yarga [219]

15 lb is nearly 6 kg amd 50 n is nearly 5 kg,so first puppy weighs more

5 0

3 years ago

An investigator places a sample 1.0 cm from a wire carrying a large current; the strength of the magnetic field has a particular

AURORKA [14]

Answer:

she must increase the current by factor of 7

Explanation:

The magnetic field produced by a steady current flowing in a very long straight wire encircles the wire.In order to solve the question, we use this formula,

B= μo I/(2πr)

where,

'μo' represents permeability of free space i.e 4π*10-7 N/A2

B=magnetic field

I= current

r=radius

->When r= 1cm=> 0.01m

B1 = μo $I_{1$ /(2π x 0.01)

->when r=7cm =>0.07m

B2 = μo $I_{2}$ /(2π x 0.07)

Now equating both of the magnetic fields, we have

B1= B2

μo $I_{1$ /(2π x 0.01)= μo $I_{2}$ /(2π x 0.07)

$I_{1$ / $I_{2}$ = 0.01/0.07

$I_{1$ / $I_{2}$ = 1/ 7

Therefore, she must increase the current by factor of 7

5 0

3 years ago

Plz help ASAP I'll mark as brainliest

gogolik [260]

Hi there!

Hooke's law states that:

F = -kx

k = Spring constant (N/m)

x = DISPLACEMENT from equilibrium (m)

Essentially, the force of a spring is PROPORTIONAL to its spring constant and its displacement from its equilibrium point.

The force of the spring (T) is not proportional to the spring's length (l), but rather its DISPLACEMENT from its equilibrium length. (Δl)

The equilibrium length is where the force of the spring (T) = 0N. Looking at the graph, the line intersects this value at l = 30cm.

We can begin by looking at the given graph.

When the spring force = 4N, the total length of the spring is 35 cm.

Now, the EQUILIBRIUM length is 30 cm, so the total elongation is:

35 - 30 = 5 cm.

5.1.

If the spring elongates by 10 cm, the total length of the spring is:

30 + 10 = 40 cm

According to the graph, a length of 40 cm corresponds to a force of 8N.

5.2.

We can solve for the weight of the ball using the following:

W (weight) = m (mass) · acceleration due to gravity (10N/kg)

Using a summation of forces:

∑F = T - W

The elongation that we are solving for occurs at the equilibrium point (net force = 0 N), so:

0 = T - W

T = W = 8 N

5.3.

0 = T - Mg

T = Mg

Use the prior value of T and gravity to solve:

8 = 10M

m = 0.8 kg

8 0

3 years ago

NEED ASAP PLEASE !!

Svetllana [295]

The balloon was 30.65 meters above ground.

ANSWER: A

3 0

3 years ago

Read 2 more answers

Based on the diagram which of the following statements is true of a helium atom

snow_lady [41]

Answer: Option 2

Explanation:

Option 1 is wrong because there are 2 protons and 2 neutrons in nucleus.

Option 3 is wrong because there are two electrons moving around nucleus.

Option 4 is wrong because electrons are negatively charged and are moving around the nucleus.

Option 5 is wrong because there equal amount of protons and electrons with 2 each.

8 0

3 years ago